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Alexus [3.1K]
3 years ago
14

How would l do this one plz help need to get this done

Mathematics
1 answer:
AnnZ [28]3 years ago
7 0
9/15 = h/7
==> 15h = 63
==> h = 4.2 ft
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What is the value of 3×2+4y2 if x=2,y=1, and z=-3
photoshop1234 [79]

3 x 2 +4y2 if y=1

3 x 2 =6

6+4y2

4 x (1) x 2 =8

8+6=

14

4 0
3 years ago
25p+1t=51<br>solve for t​
irga5000 [103]

Answer:

t = 51 - 25p

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>

<u>Algebra I</u>

  • Terms/Coefficients

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

25p + 1t = 51

<u>Step 2: Solve for </u><em><u>t</u></em>

  1. [Subtraction Property of Equality] Subtract 25p on both sides:                    1t = 51 - 25p
  2. Simplify:                                                                                                             t = 51 - 25p
5 0
3 years ago
A 100-point math test contained true/false questions worth 3 points each and short answer questions worth 11 points each. If the
TiliK225 [7]

Answer:

8

Step-by-step explanation:

100 - 12 (true or false) = 88

88/11 = 8

Hope this helps!!

happy holidays

3 0
2 years ago
A six-sided die is loaded in such a way that the probability of each face turning up is proportional to the number of dots on th
agasfer [191]

Answer:

P(2U5) = 7/21 = 1/3

the probability of getting either a 5 or a 2 in one throw is 1/3

Step-by-step explanation:

Given that; the probability of each face turning up is proportional to the number of dots on that face

P(1) = 1×P(1)

P(2) = 2×P(1)

P(3) = 3×P(1)

P(4) = 4×P(1)

P(5) = 5×P(1)

P(6) = 6×P(1)

P(T) = 21×P(1)

Where;

P(x) is the probability of getting number x on the dice.

P(T) is the total probability of obtaining any number

N(x) is the number of possible number x in terms of the distribution function.

P(x) = N(x)/N(T) ....1

And since P(T) is constant, and P(T) is proportional to N(T) then,

P(x) is directly proportional to N(x)

So, equation 1 becomes;

P(x) = N(x)/N(T) = P(x)/P(T) ....2

The probability of getting either a 5 or a 2 in one throw

P(2U5) = (P(2) + P(5))/P(T)

Substituting the values of each probability;

P(2U5) = (2P(1) + 5P(1))/21P(1)

P(2U5) = 7P(1)/21P(1)

P(1) cancel out, to give;

P(2U5) = 7/21 = 1/3

the probability of getting either a 5 or a 2 in one throw is 1/3

8 0
3 years ago
Mary went to the store and spent $4.32 on candy Jessie went to the store and spent $7.32 on snacks. How much more did Jessie spe
Liula [17]
We do 7.32-4.32 to get a $3 difference
8 0
3 years ago
Read 2 more answers
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