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Lady_Fox [76]
3 years ago
5

Solve the equation x/3 -5 =y for x.

Mathematics
1 answer:
bagirrra123 [75]3 years ago
6 0
A. X=3y + 15
I took the test last year
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Well twenty hundreds is equal to 2000 and eight tens is equal to 80. So, 2000x80=160000
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Type the number to the left of the rational number in the box to the point it represents on the number
svlad2 [7]

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I put the numbers first because it was easier for me to do but if it confuses you I can redo it

1. C

2. D

3. F

4. B

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6. A

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Find 25% of a pair of AirForce1's that cost $100.
RoseWind [281]

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it would be 25 dollors

Step-by-step explanation:

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Which of these is a linear equation in<br> standard form for the graph shown?
vampirchik [111]

Answer:

B

Step-by-step explanation:

Because the slope is a positive slope (goes through the positive quandrants on the graph), we can eliminate answer choices c. Now, if we solve a, b, and d and we can see if the slope + y-intercept matches the graph.

For A.) (solve for y to get a y=mx + b equation)

3x-2y=4

-2y= -3x + 4

<u>y= 3/2 -2</u>

For B.)

3x-2y= -4

-2y= -4-3x

<u>y= 3/2 + 2</u>

For D.)

2x+3y= 4

3y= 4-2x

<u>y= -2/3x + 4/3</u>

Now, if we look at D, the slope is negative so it cannot be D. That leaves us with A and B. The b in the y=mx + b equation stands for the y-intercept, so we can see that the y-intercept is 2. So, since the graph intersects the y-axis at (0,2), the answer is B! y=3/2 + 2 has a positive slope and 2 for the y-intercept!

4 0
3 years ago
Use the discriminant to determine how many real number solutions exist for the quadratic equation –4j2 + 3j – 28 = 0. A. 3 B. 2
Zepler [3.9K]

Answer:

C. 0

Step-by-step explanation:

–4j^2 + 3j – 28 = 0

The discriminant is b^2-4ac  if >0 we have 2 real solutions

                                                   =0  we have 1 real solutions

                                                   <0 we have 2 imaginary solutions

a = -4, b =3  c = -28

b^2 -4ac

(3)^2 - 4(-4)*(-28)

9 - 16(28)

9 -448

This will be negative so we have two imaginary solutions.

Therefore we have 0 real solutions

5 0
4 years ago
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