2 eggs are needed because if you need 4 to make 2 batches, you have to divide 4 by 2.
1,700+.05(X-600)=2,100
-1700. -1700
.05(X-600)= 400
.05x-30 =400
+30=+30
.05x=. 430
Divided by .05
X=. 8,600
Length of the outer frame: 4+2x
width of the outer frame: 3+2x
area of the outframe: (4+2x)(3+2x)=15
expand the equation: 12+8x+6x+12x^2=15
combine like terms: 4x^2+14x-3=0
![\begin{array}{llll} \textit{Logarithm of rationals} \\\\ \log_a\left( \frac{x}{y}\right)\implies \log_a(x)-\log_a(y) \end{array}~\hfill \begin{array}{llll} \textit{Logarithm Cancellation Rules} \\\\ log_a a^x = x\qquad \qquad \underset{\stackrel{\uparrow }{\textit{let's use this one}}}{a^{log_a x}=x} \end{array} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bllll%7D%20%5Ctextit%7BLogarithm%20of%20rationals%7D%20%5C%5C%5C%5C%20%5Clog_a%5Cleft%28%20%5Cfrac%7Bx%7D%7By%7D%5Cright%29%5Cimplies%20%5Clog_a%28x%29-%5Clog_a%28y%29%20%5Cend%7Barray%7D~%5Chfill%20%5Cbegin%7Barray%7D%7Bllll%7D%20%5Ctextit%7BLogarithm%20Cancellation%20Rules%7D%20%5C%5C%5C%5C%20log_a%20a%5Ex%20%3D%20x%5Cqquad%20%5Cqquad%20%5Cunderset%7B%5Cstackrel%7B%5Cuparrow%20%7D%7B%5Ctextit%7Blet%27s%20use%20this%20one%7D%7D%7D%7Ba%5E%7Blog_a%20x%7D%3Dx%7D%20%5Cend%7Barray%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)

notice, -2 is a valid value for the quadratic, however, the argument value for a logarithm can never 0 or less, it has to be always greater than 0, so for the logarithmic expression with (x-2), using x = -2 will give us a negative value, so -2 is no dice.