Answer:
the answer would be done like this
Step-by-step explanation:
you have to get y by itself so you would need to move the x to the right of the equal sign
once you move anything to the opposite side it switches, so positive becomes negative vice versa
-3y=-x+18
you need to make sure you have positive 1 y so you would divide y by -3 to make it 1
everything else is multiplied by -3 as well
so the answer would be y=⅓x-6
Answer:
Read the excerpt from "Digging"The cold smell of potato mould, the squelch and slapOf soggy peat, the curt cuts of an edgeThrough living roots awaken in my head.But I’ve no spade to follow men like them.Between my finger and my thumbThe squat pen rests.I’ll dig with it.Read the haiku by Bashō. When the winter chrysanthemums go,there’s nothing to write about but radishes.What common concern do these poems share?
Step-by-step explanation:
Read the excerpt from "Digging"The cold smell of potato mould, the squelch and slapOf soggy peat, the curt cuts of an edgeThrough living roots awaken in my head.But I’ve no spade to follow men like them.Between my finger and my thumbThe squat pen rests.I’ll dig with it.Read the haiku by Bashō. When the winter chrysanthemums go,there’s nothing to write about but radishes.What common concern do these poems share?
We know that
circumference=pi*D
where
D is the diameter
D=91 cm
so
pi-----> is the value of the calculator------> 3.1415926535897932
circumference=pi*91------> 285.88 cm------> 285.9 cm
the answer is
285.9 cm
Answer:
8 = 16
Step-by-step explanation:
1/4 = 4
/8
Cross multiply:
1 * 8 = 4 * 4
Simplifying
1 * 8 = 4 * 4
Multiply 1 * 8
8 = 4 * 4
Multiply 4 * 4
8 = 16
Solving
8 = 16
The domain of a function is the set of values of the independent variable for which the function is defined. The square root function is defined for all non-negative real numbers. So, ...
The domain of
y = √x
is all real numbers greater than or equal to zero. (x ≥ 0)
_____
In some cases, there may be other limits on the domain of a function. A function may be defined for all values of mass, for example, but is of no practical use for values of mass greater than the mass of the known universe (or planet Earth, perhaps).
