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denis-greek [22]
3 years ago
15

The mass of a bacterial culture doubles every 4 days. If the initial sample is 5 mg: a) How much will you have after one week (7

days)? b) How long does it take to reach a mass of 320mg?
Mathematics
1 answer:
jeyben [28]3 years ago
8 0

Answer:

For me i got this.  A) = 16.846mg B) 24 days I am also in summer school for toronto schoolboard.  I used the formula like how it said so should be good.

Step-by-step explanation:

A)

P(t) = Po(2)x^\frac{t}{d} \\=5(2)^\frac{7}{4} \\=16.817mg

B)

320=5(2)^\frac{t}{4}\\ 64=2^\frac{t}{4}\\2^6=2^\frac{t}{4}\\6=\frac{t}{4}\\(4)6=t \\t=24 days

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GuDViN [60]

Step-by-step explanation:

Xm = (-3+3)/2 = 0/2 = 0

Ym = (2-2)/2 = 0/2 =0

so, the midpoint (Xm, Ym) is (0 , 0)

7 0
3 years ago
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A cell phone company charges $4 per GB beyond 20GB in a month. The monthly plan is $59.99, and the bill for January is $75.99. H
Allushta [10]

Answer:

24GB

Step-by-step explanation:

75.99-59.99=16   This is how much extra money was paid.

16/4=4                   Divide this by the cost per GB.

20+4=24GB          Add the 20GB included in the plan.

3 0
4 years ago
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To get the color dove-white, Ken mixed black paint and white paint in a ratio of 5:3. He used 20 gallons of black paint. How muc
Over [174]
He used 12 gallons of white paint.

Because 20 divided by 5 = 4. Meaning that 4 gallons is one part.

4 x 5 = 20
4 x 3 = 12
4 0
4 years ago
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A researcher wanted to determine whether eating sugary cereal for breakfast increased the aggression of second graders during th
Artist 52 [7]

Answer:

20 students

Step-by-step explanation:

Sample is basically a selected subset of a population. A researcher is investigating the effect of sugary cereal on the aggression of second graders during morning play period. For this purpose, a researcher selected 20 student and feed them a sugary cereal and then observe their behaviors. Here, 20 student are selected from the all second grader students. So, the sample in the conducted study are 20 students.

5 0
4 years ago
Applying properties of Exponents in exercise,use the properties of exponents to simplify the expression.See example 1.
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Answer: a) 15625, b) 0.2, c) 625, d) 0.008.

Step-by-step explanation:

Since we have given that

a) (5^2)(5^3)

As we know that

a^m\times a^n=a^{m+n}

So, it becomes,

5^2\times 5^3=5^{2+3}=5^6=15625

(b) (5^2)(5^{-3})

So, it becomes,

5^2\times 5^{-3}=5^{2-3}=5^{-1}=\dfrac{1}{5}=0.2

(c) (5^2)^2

As we know that

(a^m)^n=a^{mn}

So, it becomes,

5^{2\times 2}=5^4=625

(d) 5^{-3}

a^{-m}=\dfrac{1}{a^m}\\\\5^{-3}=\dfrac{1}{5^3}=\dfrac{1}{125}=0.008

Hence, a) 15625, b) 0.2, c) 625, d) 0.008.

4 0
3 years ago
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