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3 years ago

help me answer these questions please for e , b and d please I know that a is 32 and I think c is 20 I think

Mathematics

2 answers:

Akimi4 [234]3 years ago

5 0

What text book do you have?

UkoKoshka [18]3 years ago

4 0

How do U do I that I do my work different lemme know how your teacher does it

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2 3 4 5 6 7 8 9 10

Igoryamba

The Answer Will Be 7:4

7 0

3 years ago

Please help, i need to raise my grade

Dmitrij [34]

Answer:

$r=\dfrac{v^2}{a}$

Step-by-step explanation:

To isolate r, we're going to need to do some algebraic manipulation.

$a=\dfrac{v^2}{r}$

Multiply both sides by r:

$a\cdot r=v^2$

Divide both sides by a:

$r=\dfrac{v^2}{a}$

Hope this helps!

5 0

3 years ago

The value 5 is an upper bound for the zeros of the function shown below.

Mice21 [21]

Answer:

The given statement that value 5 is an upper bound for the zeros of the function f(x) = x⁴ + x³ - 11x² - 9x + 18 will be true.

Step-by-step explanation:

Given

$f\left(x\right)\:=\:x^2\:+\:x^3\:-\:11x^2\:-\:9x\:+\:18$

We know the rational zeros theorem such as:

if $x=c$ is a zero of the function $f(x)$ ,

then $f(c) = 0$ .

As the $f\left(x\right)\:=\:x^2\:+\:x^3\:-\:11x^2\:-\:9x\:+\:18$ is a polynomial of degree $4$ , hence it can not have more than $4$ real zeros.

Let us put certain values in the function,

$f(5) = 448$ , $f(4) = 126$ , $f(3) = 0$ , $f(2) = -20$ ,

$f(1) = 0$ , $f(0) = 18$ , $f(-1) = 16$ , $f(-2) = 0$ , $f(-3) = 0$

From the above calculation results, we determined that $4$ zeros as

$x = -3, -2, 1,$ and $3$ .

Hence, we can check that

$f(x) = (x+3)(x+2)(x-1)(x-3)$

Observe that,

$for x > 3$ , $f(x)$ increases rapidly, so there will be no zeros for $x>3$ .

Therefore, the given statement that value 5 is an upper bound for the zeros of the function f(x) = x⁴ + x³ - 11x² - 9x + 18 will be true.

5 0

3 years ago

Suppose a simple random sample of size nequals36 is obtained from a population with mu equals 74 and sigma equals 6. (a) Descri

OlgaM077 [116]

Part a)

The simple random sample of size n=36 is obtained from a population with

$\mu = 74$

and

$\sigma = 6$

The sampling distribution of the sample means has a mean that is equal to mean of the population the sample has been drawn from.

Therefore the sampling distribution has a mean of

$\mu = 74$

The standard error of the means becomes the standard deviation of the sampling distribution.

$\sigma_ { \bar X } = \frac{ \sigma}{ \sqrt{n} } \\ \sigma_ { \bar X } = \frac{ 6}{ \sqrt{36} } = 1$

Part b) We want to find

$P(\bar X \:>\:75.9)$

We need to convert to z-score.

$P(\bar X \:>\:75.9) = P(z \:>\: \frac{75.9 - 74}{1} ) \\ = P(z \:>\: \frac{75.9 - 74}{1} ) \\ = P(z \:>\: 1.9) \\ = 0.0287$

Part c)

We want to find

$P(\bar X \: < \:71.95)$

We convert to z-score and use the normal distribution table to find the corresponding area.

$P(\bar X \: < \:71.95) = P(z \: < \: \frac{71.9 5- 74}{1} ) \\ = P(z \: < \: \frac{71.9 5- 74}{1} ) \\ = P(z \: < \: - 2.05) \\ = 0.0202$

Part d)

We want to find :

$P(73\:$

We convert to z-scores and again use the standard normal distribution table.

$P( \frac{73 - 74}{1} \:< \: z$

5 0

3 years ago

What is the solution to the system of equations? Use any method. {y=−3x+1 {2x+5y=18

Softa [21]

Answer:

So the solution set of the equations are {(-1,4)}

the solution is x = -1 and y = 4

Step-by-step explanation:

Equations given to us are

y = -3x + 1 ..................(i)

2x + 5y = 18 .................(ii)

To find the value of x and y or the solution set of the system of equations

Now in first equation we see that

y = -3x + 1

Putting this value in equation (ii)

which is

2x + 5y = 18

Putting value of y from (i) in it

2x + 5(-3x + 1) = 18

Opening the bracket and multiplying inside

2x -15x + 5 = 18

-13 x + 5 = 18

Subtracting 5 from both sides of the equation

-13x + 5 - 5 = 18 -5

-13x = 13

Dividing both sides by -13

$\frac{-13x}{-13}=\frac{13}{-13}$

Cutting out the same values gives us

x = -1

For value of y

putting value of x in equation (i)

which is

y = -3x + 1

Putting the value

y = -3(-1)+1

y=3+1

y=4

So the solution set of the equations are {(-1,4)}

the solution is x = -1 and y = 4

4 0

4 years ago

help me answer these questions please for e , b and d please I know that a is 32 and I think c is 20 I think​

help me answer these questions please for e , b and d please I know that a is 32 and I think c is 20 I think