describe how a sample of copper chloride crystals could be made from copper carbonate and dilute hydrochloric acid
1 answer:
Copper carbonate neutralises the hydrochloric acid
test formation method:-
1 put 25 ml 1M acid in beaker warm gently don't boil ( remove from heat )
2 Add the green copper carbonate powder slowly . because co2 is quickly evovled. now stir mixture
3 Continue adding powder until traces of unreacted carbonate left at bottom of beaker
4 now separate unreacted solid from green solution by filtration .
5 pour it in evapourating dish . heat over a water bath to make solution more clear
[ you can test it by dipping in a glass rod abd check if crystal form , if they formed cover the dish with piece of filter paper and let solution crystalline naturally ]
{chemical reaction of this all is attached below}
test formation method:-
1 put 25 ml 1M acid in beaker warm gently don't boil ( remove from heat )
2 Add the green copper carbonate powder slowly . because co2 is quickly evovled. now stir mixture
3 Continue adding powder until traces of unreacted carbonate left at bottom of beaker
4 now separate unreacted solid from green solution by filtration .
5 pour it in evapourating dish . heat over a water bath to make solution more clear
[ you can test it by dipping in a glass rod abd check if crystal form , if they formed cover the dish with piece of filter paper and let solution crystalline naturally ]
{chemical reaction of this all is attached below}
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