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2 years ago

Use the IUPAC nomenclature rules to give the name for this compound - Al2S3.

Chemistry

2 answers:

jonny [76]2 years ago

6 0

Aluminium Sulfide
According to rules the positive specie is named first and the negative specie is named last.

Inessa [10]2 years ago

6 0

Answer : The IUPAC name of $Al_2S_3$ is aluminum sulfide.

Explanation :

For formation of a neutral ionic compound, the charges on cation and anion must be balanced.

The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.

Ionic compound : It is a type of compound that is made up of the ions of the two different elements in which one element is a metal and another element is a non-metal.

The nomenclature of ionic compounds is given by:

Positive is written first.
The negative ion is written next and a suffix is added at the end of the negative ion. The suffix written is '-ide'.

The given compound is, $Al_2S_3$

Here aluminum is having an oxidation state of (+3) called as $Al^{3+}$ cation and sulfur $S^{2-}$ is an anion with oxidation state of (-2). Thus, they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral $Al_2S_3$ called as aluminum sulfide.

Hence, the IUPAC name of $Al_2S_3$ is aluminum sulfide.

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How many miles of C atoms are present in a sample of 3.85x1024 C atoms?

alekssr [168]

Answer:
number of moles = 6.393 moles

Explanation:
One mole of any substance contains Avogadro's number (6.022 * 10^23) of atoms.
Therefore, to know the number of moles that contain 3.85 * 10^24 atoms, all we have to do is cross multiplication as follows:
1 mole ......................> 6.022 * 10^23
?? moles ..................> 3.85 * 10^24
number of moles = (3.85 * 10^24 *1) / (6.022 * 10^23)
number of moles = 6.393 moles

Hope this helps :)

8 0

2 years ago

Which of the following oils would consume the greatest number of equivalents of hydrogen when subject to catalytic hydrogenation

Murljashka [212]

Answer: Option (B) is the correct answer.

Explanation:

When a fatty acid contains high number of double bonds then its unsaturation will also be high and hence, it will consume greater number of equivalents of hydrogen.

In corn oil, there are no unsaturated sites are present.

In olive oil, there is one unsaturated site with majority of oleic acid. In olive oil, there are more than 70% of total unsaturated oils.

In lard oil, there are around 60% of unsaturated oils.

In herring oil, there are highest number of saturated fatty acids and lowest polyunsaturated acids.

Thus, we can conclude that out of the given options, olive oils would consume the greatest number of equivalents of hydrogen when subject to catalytic hydrogenation.

5 0

3 years ago

Water flows from the bottom of a large tank where the pressure is 100 psig through a pipe to a turbine which produces 5.82 hp. T

Marianna [84]

Explanation:

Bernoulli equation for the flow between bottom of the tank and pipe exit point is as follows.

$\frac{p_{1}}{\gamma} + \frac{V^{2}_{1}}{2g} + z_{1}$ = $\frac{p_{2}}{\gamma} + \frac{V^{2}_{2}}{2g} + z_{2} + h_{f} + h_{t}$

$\frac{(100 \times 144)}{62.43} + 0 + h[tex] = [tex]\frac{(50 \times 144)}{(62.43)} + \frac{(70)^{2}}{2(32.2)} + 0 + 40 + 60$

h = $\frac{(50 \times 144)}{(62.43)} + \frac{(70)^{2}}{2(32.2)} + 40 + 60 - \frac{(100 \times 144)}{(62.43)}$

= 60.76 ft

Hence, formula to calculate theoretical power produced by the turbine is as follows.

P = mgh

= $100 \times 60.76$

= 6076 lb.ft/s

= 11.047 hp

Efficiency of the turbine will be as follows.

$\eta_{t}$ = $\frac{P_{actual}}{P_{theoretical}}$ × 100%

= $\frac{5.82}{11.047} \times 100%$

= 52.684%

Thus, we can conclude that the efficiency of the turbine is 52.684%.

4 0

3 years ago

Convert 4.0 kilometers 2 meters

Dominik [7]

4 x 1000 so 4 kilometers are equal to 4000 meters

4 0

3 years ago

naturally occurring bromine molecules, br2 have masses of 158, 160, and 162. they occur in the relative abundances 25.69%, 49.99

4vir4ik [10]

The average atomic mass of an element can be determined by multiplying the individual masses of the isotopes with their respective relative abundances, and adding them.

Average atomic mass of Br = 158 amu(0.2569) + 160 amu(0.4999) + 162 amu(0.2431)
Average atomic mass = 159.96 amu

As described in the problem, the relative abundance for Br-79 is 25.69%. This is because 2 atoms of Br is equal to 79*2 = 158 amu. Similarly, the relative abundance of Br-81 is 81*2 = 162, which is 24.31%.

4 0

2 years ago