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Blababa [14]
4 years ago
14

14. How is the number of neutrons in the nucleus of an atom calculated?

Chemistry
1 answer:
grin007 [14]4 years ago
7 0

Subtract the number of protons from the mass number.

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What is inside the nucleus of an atom
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The nucleus of a atom contains the protons and the neutrons all most all of the atoms mass is weigh by the protons and the neurons.
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How many moles of calcium (Ca) atoms are there in 77.4 g of Ca?
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Lar mass of Ca<span> = 40.08 </span>grams/mole 77.4 g Ca<span> * ( 1 </span>mole Ca<span>/ 40.08 ... n = m / M 1mol </span>Ca<span>weights 40 gmol-1 n = 77,4 / 40 = 1.93 </span>mol<span>.</span>
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What are chemical symbols and chemical formulas used for
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3 years ago
What will most likely happen when two bromine atoms bond together?
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<span>Ionic bonding is the entire exchange of valence electron(s) between particles. It is a kind of substance security that creates two oppositely charged particles. In ionic bonds, the metal loses electrons to wind up plainly an emphatically charged cation, though the nonmetal acknowledges those electrons to end up noticeably a contrarily charged anion.</span>
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Calculate the number of hydrogen atoms in a sample of hydrazine . Be sure your answer has a unit symbol if necessary, and round
gladu [14]

Answer:

atoms \ H= 9.767x10^{24}atoms

Explanation:

Hello!

In this case, considering that the mass of hydrazine is missing, we can assume it is 130.0 g (a problem found on ethernet). In such a way, since we need a mass-mole-atoms relationship by which we can compute moles of hydrazine given its molar mass (32.06 g/mol), then the moles of hydrogen considering one mole of hydrazine has four moles of hydrogen and one mole of hydrogen has 6.022x10²³ atoms (Avogadro's number); therefore, we proceed as shown below:

atoms \ H=130.0gN_2H_4*\frac{1molN_2H_4}{32.06gN_2H_4} *\frac{4molH}{1molN_2H_4} *\frac{6.022x10^{23}atoms}{1molH}\\\\atoms \ H= 9.767x10^{24}atoms

Notice 130.0 g has four significant figures, therefore the result is displayed with four as well.

Best regards!

7 0
3 years ago
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