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3 years ago

Find the median for the given set of data.5/8,3/4,1 1/8,1 1/4

Mathematics

1 answer:

Basile [38]3 years ago

8 0

Answer:

Step-by-step explanation: 15/16

I added the numbers and got 30/8

30 divided by the number of numbers (4) is 7.5

Since we are not dealing in eighths, we extrapolate that 7.5 eights = 15 sixteens, or

15/16

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Find the solution of the system of the equations 7x+14y=35 -2x-2y=-8

grandymaker [24]

Answer:

(x,y)=(309/7,-317/14) If you ever get stuck on similar problems I recommend using the photomath app.

Step-by-step explanation:

4 0

2 years ago

Can anyone help me with this

Natalka [10]

F(x) = 2x and G(x) = x^2 + 2

(G - F)(x) just means we subtract the functions from each other.

x^2 + 2 - 2x

Let's rearrange the expression

x^2 - 2x + 2

5 0

3 years ago

Read 2 more answers

Both the La Plata river dolphin (Pontoporia blainvillei) and

Citrus2011 [14]

Answer:

1. A sperm whale is 3 orders of magnitude heavier than a La Plata river dolphin; 2. The radius of the larger ball is one (1) order of magnitude bigger than the radius of the smaller ball; 3. The volume of the larger ball is 3 orders of magnitude bigger than the volume of the smaller ball.

Step-by-step explanation:

If we expressed a number as:

$\\ N = a * 10^{b}$ (1)

Where

$\\ \frac{1}{\sqrt{10}} \leq a < \sqrt{10}$ (2)

$\\ 1 \leq a < 10$ (3)

Then, b represents the order of magnitude of such a number (Order of magnitude (2020), in Wikipedia).

The order of magnitude can be defined as "...the smallest power of ten needed to represent a quantity" (Weisstein, Eric W. "Order of Magnitude". From MathWorld--A Wolfram Web Resource).

Having gathered all this information, we can proceed as follows:

<h3>First case</h3>

The La Plata river dolphin weighs between 30 and 50kg and the sperm whale weighs between 35,000 and 40,000kg.

Then, considering (1) and (3) to express the dolphin and whale's weight (since in this way the order of magnitude is the same as the exponent part in the scientific notation):

$\\ 30kg \leq Dolphin_{weight} \leq 50kg$

$\\ 3*10^{1}kg \leq Dolphin_{weight} \leq 5*10^{1}kg$

$\\ 35000kg \leq Whale_{weight} \leq 40000kg$

$\\ 3.5*10^{4}kg \leq Whale_{weight} \leq 4.0*10^{4}kg$

Since the range for the weights are in the same order of magnitude for both dolphin and whale (considering the definition above):

$\\ Dolphin_{weight} = 10^{1}\;(order\;of\;magnitude=1)$

$\\ Whale_{weight} = 10^{4}\;(order\;of\;magnitude=4)$

Then

$\\ \frac{Whale_{weight} = 10^{4}}{Dolphin_{weight} = 10^{1}}$

$\\ \frac{Whale_{weight}}{Dolphin_{weight}} = \frac{10^{4}}{10^{1}}$

$\\ \frac{Whale_{weight}}{Dolphin_{weight}} = 10^{4-1}$

$\\ \frac{Whale_{weight}}{Dolphin_{weight}} = 10^{3}$

Thus

A sperm whale is 3 orders of magnitude heavier than a La Plata river dolphin.

<h3>Second case</h3>

Following the same reasoning, we can conclude that the radius of the larger ball is one (1) order of magnitude bigger than the radius of the smaller ball:

$\\ \frac{Larger\;ball_{radius}}{Smaller\;ball_{radius}} = \frac{10^{1}}{10^{0}}$

$\\ \frac{Larger\;ball_{radius}}{Smaller\;ball_{radius}} = 10^{1-0} = 10^{1}$

<h3>Third case</h3>

For this case, we need to calculate the volume of a sphere for both radii (1cm and 10cm).

The volume of a sphere is

$\\ V_{sphere} = \frac{4}{3}*\pi*R^{3}$

Then, the volume of the ball of radius 1cm is:

$\\ V_{radius=1} = \frac{4}{3}*\pi*(1cm)^{3}$

$\\ V_{radius=1} \approx 4.19*10^{0}cm^{3}$

And, the volume of the ball of radius 10cm is:

$\\ V_{radius=10} = \frac{4}{3}*\pi*(10cm)^{3}$

$\\ V_{radius=10} \approx 4.19*10^{3}cm^{3}$

Thus

$\\ \frac{10^{3}}{10^{0}} = 10^{3}$

As a result, the volume of the larger ball is 3 orders of magnitude bigger than the volume of the smaller ball.

4 0

3 years ago

If the ribosomes were not working properly then your cell would not be producing proteins. If your cell did not produce proteins

AveGali [126]

Answer:

I think the answer is ribosomes.

Hope this helps!! <3

4 0

3 years ago

De dónde se obtienen los datos generales complementarios que se utilizan para calcular la razones de actividad

VARVARA [1.3K]

Answer:

En el departamento de ventas.

Explicación paso a paso:

Los datos generales complementarios se pueden obtener del departamento de ventas donde están presentes los datos sobre ventas y nos ayudan a calcular los ratios de actividad. El índice de actividad se puede calcular dividiendo las ventas de la empresa por sus activos totales. Este índice de actividad indica la eficiencia de una empresa mediante el uso de sus activos disponibles para producir ventas. El índice de actividad también se denomina "Índice de gestión de activos". Los datos de ventas son necesarios para el índice de actividad que puede estar disponible en el departamento de ventas.

8 0

3 years ago