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mina [271]
3 years ago
8

Which sequence of transformations results in figures that are similar but not congruent?

Mathematics
1 answer:
PolarNik [594]3 years ago
4 0
Maybe the answer is b try it
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Use the relationships in the diagram to find the value of C<br> 520<br> d<br> 379<br> 63
Brut [27]

Answer:

c = 154°

Step-by-step explanation:

I Hope this helps.

7 0
3 years ago
A 1,127-foot tree has grown at a constant rate each year. In the equation below, t is the age of the tree in years.
Lisa [10]

Answer:

Your answer will be 17

Step-by-step explanation:

Simply multiply and take away the t and add into the 9+ after your equation

3 0
4 years ago
The histogram to the right represents the weights​ (in pounds) of members of a certain​ high-school programming team. What is th
AVprozaik [17]

Answer:

Class width=20

Lower class limit of first class=100

Upper class limit of first class=120

Step-by-step explanation:

The class width can be calculated by taking the difference of two consecutive upper class limits or lower class limits.

Now we take any two consecutive upper class limits or lower class limits from classes 100-120,120-140,140-160,160-180,180-200,200-220,220-240.

We take upper class limits of first and second class i.e. 100 and 120.

Class width=120-100=20

Class width=20

The approximate lower and upper class limits of the first class from classes  100-120,120-140,140-160,160-180,180-200,200-220,220-240 are 100 and 120.

Class limits for first class is 100-120.

Lower class limit of first class=100

Upper class limit of first class=120

4 0
3 years ago
Show how to work out the problem 16.31-8.764
irakobra [83]
The answer would be 7.564

Here is the work and next to it I checked the answer

6 0
3 years ago
Trigonometry:<br> Simplify the expression.<br><br> (cot²α - 4) / (cot²α - cotα - 6)
Anettt [7]
<span>(cot²α - 4) / (cot²α - cotα - 6);  Let x = </span><span>cotα

Therefore  </span><span>(cot²α - 4) / (cot²α - cotα - 6)   = </span><span>(x²- 4) / (x² - x - 6)
</span>
(x²- 4) =  <span>x² - </span><span>2² = (x-2)(x+2)  . Difference of two squares.

</span><span>(x² - x - 6);  This is a quadratic expression,
Multiply the first and last terms = -6</span>x²
we think of two expression that multiply to give -6x² and add up to give -x (Middle term)

Those expression are 2x and -3x
(x² - x - 6) = <span>(x² +2x-3x - 6) = x(x+2) -3(x+2) = </span>(x+2)<span><span>(x-3)

</span> Recall </span><span>(x²- 4) / (x² - x - 6) = (</span><span>(x-2)(x+2)) / (</span><span>(x+2)<span>(x-3)) = </span></span><span>(x-2)/</span><span><span>(x-3). Cancelling out.</span> </span>

Recall  x = <span>cotα, therefore:</span>
(x-2)/<span>(x-3) = </span>(cotα-2)/(cotα-3)

(cot²α - 4) / (cot²α - cotα - 6)  =  (cotα-2)/(cotα-3)

7 0
3 years ago
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