All categories

3 years ago

Write a standard form of a quadratic equation that has roots - 5/2 and 3.

Mathematics

1 answer:

lora16 [44]3 years ago

6 0

Answer:

2x^2 - x - 15 = 0.

Step-by-step explanation:

In factor form this is

(x + 5/2)(x - 3) = 0

x^2 + 5/2x - 3x - 15/2 = 0

x^2 - 1/2x - 15/2 = 0

Multiply through by 2:

2x^2 - x - 15 = 0.

You might be interested in

. 2(x + 4) = -5x + 1 what the equation?<br>

weqwewe [10]

X=-1
Collect the like terms
And then divide both sides by seven

4 0

3 years ago

The number of people arriving for treatment at an emergency room can be modeled by a Poisson Distribution with a rate parameter

AlekseyPX

Answer:

a) 0.052 = 5.2% probability that exactly three arrivals occur during a particular hour

b) 0.971 = 97.1% probability that at least three people arrive during a particular hour

c) 5.25 people are expected to arrive during a 45-min period

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Poisson Distribution with a rate parameter of seven per hour.

This means that $\mu = 7$

(a) What is the probability that exactly three arrivals occur during a particular hour?

This is P(X = 3).

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 3) = \frac{e^{-7}*7^{3}}{(3)!} = 0.052$

0.052 = 5.2% probability that exactly three arrivals occur during a particular hour.

(b) What is the probability that at least three people arrive during a particular hour? (Round your answer to three decimal places.)

Either less than three people arrive, or at least three does. The sum of the probabilities of these events is 1. So

$P(X < 3) + P(X \geq 3) = 1$

We want $P(X \geq 3)$ , which is

$P(X \geq 3) = 1 - P(X < 3)$

In which

$P(X \geq 3) = P(X = 0) + P(X = 1) + P(X = 2)$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-7}*7^{0}}{(0)!} = 0.001$

$P(X = 1) = \frac{e^{-7}*7^{1}}{(1)!} = 0.006$

$P(X = 2) = \frac{e^{-7}*7^{2}}{(2)!} = 0.022$

$P(X \geq 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.001 + 0.006 + 0.022 + 0.029$

$P(X \geq 3) = 1 - P(X < 3) = 1 - 0.029 = 0.971$

0.971 = 97.1% probability that at least three people arrive during a particular hour

(c) How many people do you expect to arrive during a 45-min period?

During an hour(60 minutes), 7 people are expected to arrive. So, using proportions:

$\frac{45*7}{60} = \frac{3*7}{4} = \frac{21}{4} = 5.25$

5.25 people are expected to arrive during a 45-min period

5 0

3 years ago

Explain why the fractions in question number 2 are equivalent?

NISA [10]

Answer:

its 2/6ths its only multiplied by 2

Step-by-step explanation:

4 0

2 years ago

How to add -89 and 17 step by step

Debora [2.8K]

Step-by-step explanation: The easiest way to do this and the way I commonly use is to subtract 17 from 89then make it negative as you are making the negative number smaller by adding a smaller number therefore your answer is -72

6 0

3 years ago

Is 1,000 a rational number or a irrational or is it a whole number ?

ad-work [718]

Answer:

1,000 is both a rational number and a whole number.

If my answer helped, please mark me as the brainliest!!

Thank You!!

3 0

3 years ago