Answer:
0.0217 m
Explanation:
Ftom the question,
Applying Coulomb's law
F = kqq'/r²............... Equation 1
Where F = Electric Force, q and q' = First and second charge respectively, r = distance between the charges, k = coulomb's constant.
make r the subeject of the equation
r = √[(kqq')/F]............. Equation 2
Given: q = +3.6×10⁻⁸ C, q' = -3.2×10⁻⁸ C, F = -2.2×10⁻² N
Constant: k = 8.98×10⁹ Nm²/C²
Substitute these values into equation
r = √(+3.6×10⁻⁸×-3.2×10⁻⁸×8.98×10⁹/-2.2×10⁻²)
r = √(-103.4489×10⁻⁷/-2.2×10⁻²)
r = √(47.02×10⁻⁵)
r = 21.68×10⁻³
r ≈ 21.7×10⁻³ m.
r ≈ 0.0217 m
Hence the seperation between the two balloons is 0.0217 m
Answer: Yes it is indeed
Explanation: I understand cuz school is like a prison lol
F = mass * acceleration
The 80kg hockey player was travelling at 5 m/s when he hit the wall.He stopped in .2 s, which means that he decelerated by 5m/s in .2 seconds.
This means this deceleration was 5 m / 0.2 s² = 25 m/s²
To calculate Force, multiply mass times acceleration
80kg times 25m/s² = 2,000 N