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Rudik [331]
2 years ago
11

How can we show magnetic field lines?

Physics
2 answers:
aleksklad [387]2 years ago
8 0

<em>Magnetic fields can be mapped out using small plotting compasses : place the plotting compass near the magnet on a piece of paper. move the plotting compass to many different positions in the magnetic field, marking the needle direction each time. join the points to show the field lines.</em>

lara [203]2 years ago
7 0

Answer:

Magnetic field lines are defined to have the direction that a small compass points when placed at a location. (a) If small compasses are used to map the magnetic field around a bar magnet, they will point in the directions shown: away from the north pole of the magnet, toward the south pole of the magnet.

Explanation:

have a beautiful day ahead

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A ball is thrown horizontally from the top of a building 21.8 m high. The ball strikes the ground at a point 101 m from the base
riadik2000 [5.3K]

Answer:

t=2.10 s

u= 47.40 m/s

Explanation:

given that

h= 21.8 m

x= 101 m

g=9.8 m/s²

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The vertical speed of the car at initial condition is zero ( v= 0).

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h=vt+\dfrac{1}{2}gt^2

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now by putting the values

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6 0
2 years ago
An object is 15 cm in front of a diverging lens with a
Rainbow [258]

A) See ray diagram in attachment (-6.0 cm)

By looking at the ray diagram, we see that the image is located approximately at a distance of 6-7 cm from the lens. This can be confirmed by using the lens equation:

\frac{1}{q}=\frac{1}{f}-\frac{1}{p}

where

q is the distance of the image from the lens

f = -10 cm is the focal length (negative for a diverging lens)

p = 15 cm is the distance of the object from the lens

Solving for q,

\frac{1}{q}=\frac{1}{-10 cm}-\frac{1}{15 cm}=-0.167 cm^{-1}

q=\frac{1}{-0.167 cm^{-1}}=-6.0 cm

B) The image is upright

As we see from the ray diagram, the image is upright. This is also confirmed by the magnification equation:

h_i = - h_o \frac{q}{p}

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Since q < 0 and p > o, we have that h_i >0, which means that the image is upright.

C) The image is virtual

As we see from the ray diagram, the image is on the same side of the object with respect to the lens: so, it is virtual.

This is also confirmed by the sign of q in the lens equation: since q < 0, it means that the image is virtual

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