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3 years ago

How can we show magnetic field lines?

2 answers:

8 0

Magnetic fields can be mapped out using small plotting compasses : place the plotting compass near the magnet on a piece of paper. move the plotting compass to many different positions in the magnetic field, marking the needle direction each time. join the points to show the field lines.

lara [203]3 years ago

7 0

Answer:

Magnetic field lines are defined to have the direction that a small compass points when placed at a location. (a) If small compasses are used to map the magnetic field around a bar magnet, they will point in the directions shown: away from the north pole of the magnet, toward the south pole of the magnet.

Explanation:

have a beautiful day ahead

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2. Place the pairs in order from weakest to strongest gravitational force. (Brainpop Gravity Challenge)

FromTheMoon [43]

Answer:

B, A, C, D

Explanation:

i hope it helps. im just kinda guessing.

good luck!°°°°°⁰⁰⁰⁰⁰₀₀₀₀₀oo00OO

3 0

3 years ago

Measuring the diameter of a specific object might include which pair of SI units

VLD [36.1K]

Well, the diameter of a circle is simply a length, so your measurement will have units of length. We just have to find an answer that has only units of length.

A). gram, second . . . mass and time. That can't be it.

B). kilogram, ampere . . . mass and current. That can't be it.

C). centimeter, meter . . . both lengths. This one is looking good.

D). candela, mole . . . light intensity and some chemical thing. That can't be it.

So it can't be anything else on this list but C .

8 0

3 years ago

Car A with a mass of 725 kilograms is traveling east at an initial velocity of 15 meters/second. It collides head–on with car B,

ikadub [295]

Answer:

$p_t_o_t_a_l=250kg\frac{m}{s}$

Explanation:

The total momentum of a system is defined by:

$(mv)_t_o_t=m_1v_1+m_2v_2+...$

Where,

$(mv)_t_o_t$ is the total momentum or it could be expressed also as $p_t_o_t_a_l$ .

$m_1$ and $m_2$ represents the masses of the objects interacting in the system.

$v_1$ and $v_2$ are the velocities of the objects of the system.

Remember: The momentum is a fundamental physical magnitude of vector type.

We have:

$m_1=725 kg$

$v_1=15\frac{m}{s}\\m_2=625 kg$

We are going to take the east side as positive, and the west side as negative. Then the velocity of the car B, has to be negative. It goes in a different direction from car A.

$v_2=-17\frac{m}{s}$

Then the total momentum of the system is:

$p_t_o_t_a_l=m_1v_1+m_2v_2\\p_t_o_t_a_l=(725kg)(15\frac{m}{s})+(625kg)(-17\frac{m}{s})\\p_t_o_t_a_l=10875kg\frac{m}{s}-10625kg\frac{m}{s}\\p_t_o_t_a_l=250kg\frac{m}{s}$