Speed v = initial speed u + acceleration a x time t
v=u+at = 2 + 4*3 = 14 m/s
Between 9:00 am and 10:45 am, there have been 1 hour and 45 minutes or 1.75 hours have passed. Let x be the speed of the slower cyclist and x+ 5 be the rate of the second cyclist. The given situation is best represented through the equation below,
x(1.75) + (x + 5)(1.75) = 47.25 km
The value of x from the equation is 11. Thus, the two bicyclists' rates are 11 km/h and 16 km/h.
Answer:
Magnitude = 3.64 × 
စ = 43.9°
Explanation:
given data
ship to travel = 1.7 × kilometers
turn = 70°
travel an additional = 2.7 × kilometers
solution
we will consider here
Px = 1.7 ×
Py = 0
Qx =2.7 × cos(70)
Qy= 2.7 × sin(70)
so that
Hx = Px + Qx ............1
Hx = 2.62 ×
and
Hy = Py + Qy ..........2
Hy = 2.53 ×
so Magnitude = 
Magnitude = 3.64 ×
so direction will be
tan စ = Hy ÷ Hx ......................3
tan စ = 
tan စ = 0.9656
စ = 43.9°
Answer: They travel equal distances
Explanation:
Distance is amount of space covered from one point to another. It is measured in metres. Distance = speed x time taken
In this case,
- Since Tony and Tanya both run at the same speed: let speed = b
- Also, both run for the same amount of time: let time = c
Therefore, distance covered by Tony and Tanya = speed x time taken
Distance = b x c
Distance = bc (i.e Tony travelled a distance of bc, so also Tanya)
