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kolbaska11 [484]
4 years ago
11

Which is not an example of how an object gains elastic potential energy by stretching?

Physics
1 answer:
lora16 [44]4 years ago
4 0
C because you don’t put a force of which you choose and the force wouldn’t be strong enough
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A 6.2 kg ladder, 1.97 m long, rests on two sawhorses. Sawhorse A is 0.64 m from one end of the ladder, and sawhorse B is 0.17 m
Keith_Richards [23]

Answer:

42.69 N and 18.07 N

Explanation:

We are given that

Mass of ladder=6.2 kg

Length of ladder=1.97 m

Distance of Sawhorse A from one end=0.64 m

Distance of sawhorse B from other end=0.17 m

Let center of Ladder=\frac{1.97}{2}=0.985 m

Now, the distance of sawhorse A from center=r=0.985-0.64=0.345 m

Distance of sawhorse B from center of ladder=0.985-0.17=0.815  m

Force one ladder due to gravity=mg=6.2\times 9.8=60.76N

Where g=9.8 m/s^2

Torque applied on Sawhorse A=0.345F_a

Torque applied on Sawhorse B=0.815F_b

In equilibrium

0.345F_a=0.815F_b

F_b=\frac{0.345}{0.815}F_a

Total force=F_a+F_b

F_a+\frac{0.345}{0.815}F_a=60.76

\frac{0.815F_a+0.345F_a}{0.815}=60.76

\frac{1.16}{0.815}F_a=60.76

F_a=\frac{60.76\times 0.815}{1.16}=42.69 N

F_b=\frac{0.345}{0.815}\times 42.69=18.07 N

8 0
4 years ago
A uniform narrow tube 1.90 m long is open at both ends. It resonates at two successive harmonics of frequencies 280 Hz and 294 H
Over [174]

Answer:

a)14Hz

b)26.6m/s

Explanation:

a)we were given

the first harmonics frequencies as 280 Hz

The second harmonic frequency as 294 Hz.

The fundamental frequency is equal to the gap which means the distance that exist between the harmonics, then

the fundamental frequency=(294 - 280 = 10 Hz)

= 14Hz

b) We know the frequency and the wavelength of the sound wave (

We were told that the wavelength must be twice the length of the tube then, velocity can be calculated as

And fundamental frequency= 14Hz, and distance of 1.90 m then

v = f*2L = (14Hz)*2*(1.90 m) = 26.6m/s

Therefore, the speed of sound in the gas in the tubes is 26.6m/s

7 0
3 years ago
Why hail is sometimes dangerous
Bogdan [553]
Because it’s hard snow that can kill you
7 0
3 years ago
Read 2 more answers
A massless string connects a 10.00 kg mass to a 13.00 kg cart which is resting on a frictionless horizontal surface. The mass ha
ch4aika [34]

The cart's acceleration to the right after the mass is released  is determined as 7.54 m/s².

<h3>Acceleration of the cart</h3>

The acceleration of the cart is determined from the net force acting on the mass-cart system.

Upward force = Downward force

ma = mg

13a = 10(9.8)

13a = 98

a = 98/13

a = 7.54 m/s²

Thus, the cart's acceleration to the right after the mass is released  is determined as 7.54 m/s².

Learn more about acceleration here: brainly.com/question/14344386

#SPJ1

6 0
2 years ago
The planet Jupiter orbits the Sun at a nearly constant speed. Which of the following statements are true?
RoseWind [281]

Answer:

a. There is a force on Jupiter toward the center of the orbit.

d. Jupiter is accelerating toward the center of the orbit.

Explanation:

Let us look at each of the choices one by one:

a. There is a force on Jupiter toward the center of the orbit.

True. The sun being at the center of Jupiter's orbit, pulls the planet towards it (providing the centripetal force), therefore, there exists a force on Jupiter toward the center of the orbit.

b. There is a force on Jupiter pulling it out from the center of the orbit.

Nope. The centripetal force due to gravity acts towards the center of the orbit.  

c. There is a force on Jupiter in the direction of its motion.

Nope. There exists only the centripetal force acting towards the center of the orbit,

d. Jupiter is accelerating toward the center of the orbit.

Yes. Because of the centripetal force gravity provides, Jupiter is accelerating towards the center of the orbit, but it does not fall in because it has velocity perpendicular to the direction of its acceleration.

6 0
3 years ago
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