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yuradex [85]
3 years ago
11

Which of the following quantities has the same dimensions as a speed? and why?

Physics
1 answer:
saveliy_v [14]3 years ago
6 0

Answer:

the answer is at

Explanation:

Dimension of at = [ LT^-2 ] [ T ]

= [ LT^(-2+1) ]

= [ LT^-1 ]

which is same as dimension of speed.

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A string attached to an airborne balloon was maintained at an angle of 54 degrees with the ground. If 2.3 m of string was reeled
Slav-nsk [51]

Answer:

dₓ = 1.35 m

dy = 1.86 m

Explanation:

In order to find the vertical and horizontal components of the displacement, we can assume a right triangle. Such that, the length of string is the hypotenuse, making and angle of 54° with the base of triangle. The base is the horizontal component of displacement. And the perpendicular is the vertical component of displacement. Therefore:

d_{x} = d\ Cos\ \theta

where,

dₓ = horizontal component of displacement = ?

d = resultant displacement = 2.3 m

θ = angle between displacement and ground = 54°

Therefore,

d_{x} = (2.3\ m)\ Cos\ 54^0

<u>dₓ = 1.35 m</u>

For vertical component of displacement:

d_{y} = d\ Sin\ \theta\\d_{y} = (2.3\ m)\ Sin\ 54^0

<u>dy = 1.86 m</u>

8 0
3 years ago
How many minutes will it take you to finish a 5 km race at an average speed of 7.0m/s?
slava [35]

Answer:

11.9 minutes

Explanation:

The journey is 5000 meters long. The time it takes in seconds for the journey at this speed is 5000/7 =714 seconds.

714/60=time in minutes =11.9 minutes approximately.

6 0
3 years ago
A car has an initial velocity of 0m/s. It accelerates at a rate of 5m/s2 and travels 30m. What is the final velocity?
Eduardwww [97]

Answer:

2.5m/s1

Explanation:

8 0
2 years ago
Read 2 more answers
If an airplane is moving at a constant speed of 500 miles per hour in a straight line is it accelerating?
Zinaida [17]

No. It’s moving at a constant speed (speed is not changing) in a straight line (same direction so velocity is not changing) so it is not accelerating. Acceleration only occurs if there’s a change in speed/velocity.

4 0
4 years ago
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At t = 0 the end you are oscillating is at its maximum positive displacement and is instantaneously at rest. Write an equation f
vovikov84 [41]

Answer:

The equation of displacement is y=A\sin(\omega t-2.50 k+\dfrac{\pi}{2}).

Explanation:

Given that,

Distance = 2.50 m

We need to calculate the equation of wave

Using general equation of wave

y=A\sin(\omega t-kx+\phi)....(I)

Where, A = amplitude

t = time

x = displacement

\phi = phase difference

Put the value in the equation

At t = 0, x = 0, y =A

A=A\sin(0+\phi)

\sin\phi=1

\phi=\dfrac{\pi}{2}

From equation (I)

y=A\sin(\omega t-2.50 k+\dfrac{\pi}{2})

Hence, The equation of displacement is y=A\sin(\omega t-2.50 k+\dfrac{\pi}{2}).

7 0
3 years ago
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