Answer:
For carbon 12
ΔV1 = 2265.31 V
ΔV2 = 362.5 V
For carbon 14
ΔV1 = 1941.7 V
ΔV2 = 310.67 V
Explanation:
The complete explanations are given in the attachment below. The formulae for the accelerating potential ΔV1 and ΔV2 are derived and the necessary parameters are substituted into the derived equations.
Answer:
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This depends on whether the pipe is closed or open ended.
The fundamental frequency of a pipe is the simplest, smallest portion of a wave that can fit into a pipe. At the open end of a pipe, there is always an antinode - an area with maximum air movement.
If it is an open ended pipe, there is an antinode at each end, meaning that the length of the pipe is equal to 1/2 <span>λ
</span>. Manipulating the formula <span><span>v=fλ</span>
</span> to solve for the fundamental frequency leaves us with <span><span>f=<span>v/<span>2L</span></span></span>
</span> in an open ended pipe.
Isothermal process<span> is a </span>change<span> of a </span>system<span>, in which the </span>temperature<span> remains constant: Δ</span>T<span> = 0. So, if the thermodynamic process takes place at a constant temperature so that the internal energy of a system remains unchanged than this process is isothermal.
</span><span>The Joule's second Law states that the internal energy of a fixed amount of an ideal gas depends only on its temperature. So, isothermal processes are of great interest for ideal gasses.</span>
