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3 years ago

3. Solve each equation, and check your solution.

Mathematics

1 answer:

Alisiya [41]3 years ago

7 0

1) 2m - 16 = 2m + 4

2m - 2m = 4 + 16

0 = 20 (no solution)

2) -4(r + 2) = 4(2 - 2r)

-(r + 2) = 2 - 2r

-r - 2 = 2 - 2r

-r + 2r = 2 + 2

r = 4

3) 12(5 + 2y) = 4y - (6 - 9y)

60 + 24y = 4y - 6 + 9y

60 + 24y = 13y - 6

24y - 13y = -6 - 60

11y = -66

y = -6

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2 years ago

When a breeding group of animals is introduced into a restricted area such as a wildlife reserve, the population can be expected

jasenka [17]

Answer:

A. Initially, there were 12 deer.

B. N(10) corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.

C. After 15 years, there will be 410 deer.

D. The deer population incresed by 30 specimens.

Step-by-step explanation:

$N=\frac{12.36}{0.03+0.55^t}$

The amount of deer that were initally in the reserve corresponds to the value of N when t=0

$N=\frac{12.36}{0.33+0.55^0}$

$N=\frac{12.36}{0.03+1} =\frac{12.36}{1.03} = 12$

A. Initially, there were 12 deer.

B. $N(10)=\frac{12.36}{0.03 + 0.55^t} =\frac{12.36}{0.03 + 0.0025}=\frac{12.36}{y}=380$

B. N(10) corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.

C. $N(15)=\frac{12.36}{0.03+0.55^15}=\frac{12.36}{0.03 + 0.00013}=\frac{12.36}{0.03013}= 410$

C. After 15 years, there will be 410 deer.

D. The variation on the amount of deer from the 10th year to the 15th year is given by the next expression:

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2 years ago

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Korolek [52]

Answer:

your rue

Step-by-step explanation:

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2 years ago

Classify the expression 2x-x+5

lapo4ka [179]

First simplify the expression as much as possible.

2x - x + 5

2x - x = x

x + 5

There are two terms, x and 5. expressions that have two terms are known as binomials

binomials should be your answer.

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2 years ago