Answer:
Option D is correct i.e., =DATEDIF(C2, $AE$2, "y").
Explanation:
The user's supervisor well into the following department tells him to compose the feature which measures the amount that times staff has served in their company utilizing the DATEDIF feature. Consider whether C2 includes the hiring dates for that staff and then that cell $AE$2 includes the cut-off point for whom to evaluate the hiring time with the duration of the service.
So, therefore the following option is correct according to the given scenario.
Answer:
Ransomware is malicious software that infects your computer and displays messages demanding a fee to be paid in order for your system to work again. It has the ability to lock a computer screen or encrypt important, predetermined files with a password.
Explanation:
:)
Answer:
The answer to this question is given below in the explanation section.
Explanation:
The correct answer to this question is d- 346px.
The complete code of this example is given below:
<div>
style="margin:20px; border:solid 3px #888888;">
</div>
while the image width is 300px.
It is noted that the image width is 300px and the margin is 20 px.
Margin:20px means that image margin from four side is 20 px each.
So the width of dive from both side increase to 40 px and the image has 300 px, then total width becomes 340px. Now the border also has 3px of four sides of the image, then the width of the border becomes 6px.
so the total width of the div tag is 346 px.
In short, we can calculate the width of tag as below:
total width of div= width of image+ width of margin+ width of border
total width of dive= 300px+40px+6px
total width of div=346px.
Hey mate thanks for letting me help you
l just look into this and l got this A set of APIs to create and display a (compound) document, but that is not a choice. so <span>D. edit data in a plain text editor
</span><span>
hope l helped
</span>
For the view of Exercise 4.18, explain why the database system would not allow a tuple to be inserted into the database through this view.
For reference
For the database of Figure 4.12, write a query to find the ID of each employee with no manager. Note that an employee may simply have no manager listed or may have a null manager. Write your query using an outer join and then write it again using no outer join at all.
OUTER JOIN
select e.ID from employee e left outer join manages m on e.ID = m.ID
where m.manager_id is null;
NO OUTER
select e.ID from employee e where e.ID not in (select m.ID from manages m) or e.ID in (select m.ID from manages m where m.manager_id is null);
