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3 years ago

All of the following are stages in the SDLC except _____.

Computers and Technology

1 answer:

Anni [7]3 years ago

3 0

All of the following are stages in the SDLC except JAD. JAD is Joint Application Development.

Explanation:

JAD (Joint Application Development) is a methodology that involves the client or end user in the design and development of an application, through a succession of collaborative workshops called JAD sessions.
The JAD approach, in comparison with the more traditional practice, is thought to lead to faster development times and greater client satisfaction, because the client is involved throughout the development process. In comparison, in the traditional approach to systems development, the developer investigates the system requirements and develops an application, with client input consisting of a series of interviews.
JAD is a process used in the life cycle area of the dynamic systems development method (DSDM) to collect business requirements while developing new information systems for a company.
The JAD process also includes approaches for enhancing user participation, expediting development, and improving the quality of specifications.

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A client contacted you to request your help in researching and supplying the hardware necessary to implement a SOHO solution at

Tcecarenko [31]

Answer:

Option 2 i.e., DHCP server.

Explanation:

A client approached the user to ask about their support towards investigating as well as providing necessary equipment required for implementing a SOHO system for his latest house corporation.

So, the following SOHO router functionality facilitates the installation of IP addresses both for the cable and wireless networks on the private server.

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3 years ago

How can you enter Task Manager in Windows? Select 3 options. press Ctrl + Shift + Tab press Ctrl+Alt+Delete and then click Task

Sophie [7]

Answer:

Please find the 3 options below.

Explanation:

To begin with, Task Manager in windows, is a monitor program that provides information or shows application and processes running on a computer. Task manager also provide insights about the general status of a computer. The three options for entering or accessing task manager in windows are:

1. Press Ctrl+Alt+Delete and then click Task Manager

2. Right-click the taskbar and choose Start Task Manager

3. Right-click the taskbar and choose Manage Tasks

5 0

4 years ago

List five applications field of a computer?

True [87]

list five applications field of a computer?

answer=  home , school, hospital, bank, super markets, etc....

5 0

3 years ago

CHALLENGE ACTIVITY |

fredd [130]

Answer:

maxSum = FindMax(numA, numB) + FindMax(numY, numZ);

The maxSum is a double type variable which is assigned the maximum of the two variables numA numB PLUS the maximum of the two variables numY numZ using FindMax function. The FindMax() method is called twice in this statement one time to find the maximum of numA and numB and one time to find the maximum of numY numZ. When the FindMax() method is called by passing numA and numB as parameters to this method, then method finds if the value of numA is greater than that of numB or vice versa. When the FindMax() method is called by passing numY and numZ as parameters to this method, then method finds if the value of numY is greater than that of numZ or vice versa. The PLUS sign between the two method calls means that the resultant values returned by the FindMax() for both the calls are added and the result of addition is assigned to maxSum.

Explanation:

This is where the statement will fit in the program.

#include <iostream>

using namespace std;

double FindMax(double num1, double num2) {

double maxVal = 0.0;

if (num1 > num2) { // if num1 is greater than num2,

maxVal = num1; // then num1 is the maxVal. }

else {

maxVal = num2; // num2 is the maxVal. }

return maxVal; }

int main() {

double numA;

double numB;

double numY;

double numZ;

double maxSum = 0.0;

maxSum = FindMax(numA, numB) + FindMax(numY, numZ);

cout << "maxSum is: " << maxSum << endl; }

Lets take an example to explain this. Lets assign values to the variables.

numA = 6.0

numB = 3.0

numY = 4.0

numZ = 9.0

maxSum =0.0

maxSum = FindMax(numA, numB) + FindMax(numY, numZ);

FindMax(numA,numB) method call checks if numA>numB or numB>numA and returns the maximum of the two. Here numA>numB because 6.0 is greater than 3.0. So the method returns numA i.e. 6.0

FindMax(numY, numZ) method call checks if numY>numZ or numZ>numY and returns the maximum of the two. Here numZ>numY because 9.0 is greater than 4.0. So the method returns numZ i.e. 9.0

FindMax(numA, numB) + FindMax(numY, numZ) this adds the two values returned by the method FindMax for each call.

FindMax returned maxVal from numA and numB values which is numA i.e. 6.0.

FindMax returned maxVal from numY and numZ values which is numZ i.e. 9.0.

Adding these two values 9.0 + 6.0 = 15

So the complete statement FindMax(numA, numB) + FindMax(numY, numZ) gives 15.0 as a result.

This result is assigned to maxSum. Hence

maxSum = 15

To see the output on the screen you can use the print statement as:

cout<<maxSum;

This will display 15

6 0

3 years ago

Organ transplants are rarely successful.

Maurinko [17]

False......................

6 0

3 years ago