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3 years ago

Help ppppppppppppllllllllllllllllsssssssss

Mathematics

2 answers:

Zigmanuir [339]3 years ago

6 0

<h2>Answer:</h2>

<u>The right choice is option </u><u>(B) tan²θ + 1 = sec²θ</u>

<h2>Step-by-step explanation:</h2>

1 + (sin²θ/cos²θ)

= (cos²θ/cos²θ) + (sin²θ/cos²θ)

= (cos²θ + sin²θ) / cos²θ

= 1/cos²θ

= sec²θ

marissa [1.9K]3 years ago

4 0

Answer:

option b)

tan²θ + 1 = sec²θ

Step-by-step explanation:

The Pythagorean trigonometric identity is a trigonometric identity expressing the Pythagorean theorem in terms of trigonometric functions.

hypotenuse² = height² + base²

Given in the questions are some pythagorus identities which except of b) are all incorrect as explained below.

sin²θ + 1 = cos²θ incorrect

<h3>sin²θ + cos²θ = 1 correct</h3><h3 /><h3>2)</h3>

by dividing first identity by cos²θ

sin²θ/cos²θ + cos²θ/cos²θ = 1/cos²θ

<h3>tan²θ + 1 = sec²θ correct</h3><h3 /><h3>3)</h3>

1 - cot²θ = cosec²θ incorrect

by dividing first identity by sin²θ

sin²θ/sin²θ + cos²θ/sin²θ = 1/sin²θ

<h3>1 + cot²θ = cosec²θ correct</h3><h3 /><h3>4)</h3>

1 - cos²θ = tan²θ

not such pythagorus identity exists

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