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2 years ago

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A blueprint of a house has a scale of 1 in : 6ft. The living room has a dimensions of 18 ft x 24 feet. What are the dimensions o

n the blueprint of the living room

1 answer:

Mumz [18]2 years ago

5 0

The dimensions are 3 in x 4 in

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What would be the solution to 5(g+4)>15? And how would it look like on a number line/graph?

WITCHER [35]

G>-1 is your solution and it would look like this on a graph..( see below)

3 0

3 years ago

The point (0, 0) is a solution to which of these inequalities?

adell [148]

Since - 5 is less than -4, hence the point (0, 0) is a solution to the inequality y-5<3x-4

<h3>Solution to inequality expression</h3>

Inequality are equations not separated by an equal sign. Given the inequality

y-5<3x-4

Check if (0, 0) is a solution

0 - 5 < 3(0) - 4

-5 < -4

Since - 5 is less than -4, hence the point (0, 0) is a solution to the inequality y-5<3x-4

learn more on inequality here: brainly.com/question/24372553

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2 years ago

a patio is 6.21 meters and its width is 5.7 what is the approximate perimeter of the patio round your answer to nearest whole nu

Leto [7]

Answer:7.5

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

quinn leaves her house at 10:00 am and runs 3 miles at a steady pace of 6 miles per hour. she relaxes and takes a lunch break fo

Usimov [2.4K]

Answer:

1 hour 45 minutes

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Five students visiting the student health center for a free dental examination during National Dental Hygiene Month were asked h

Andrews [41]

Answer:

[0.9 months, 32.69 months]

Step-by-step explanation:

The mean is

$\bf \bar x=\frac{5+17+12+21+29}{5}=16.8$

The standard deviation is

$\bf s=\sqrt{\frac{(5-16.8)^2+(17-16.8)^2+(12-16.8)^2+(21-16.8)^2+(29-16.8)^2}{5}}=8.1092$

Now, we have to find two values a and b such that the area under the Normal curve with mean 16.8 and standard deviation 8.1092 between a and b equals <em>95% = 0.95 </em>

Using a spreadsheet we find these values are

a = 0.906

b = 32.694

<h3>(See picture) </h3>

and our 95% confidence interval for the mean number of months elapsed since the last visit to a dentist for the population of students participating in the program rounded to two decimal places is

[0.9 months, 32.69 months]

4 0

3 years ago