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IrinaK [193]
3 years ago
14

What is the length of line AB in the given triangle? A.) 8 B.)8.3 C.)6.6 D.)9.7

Mathematics
1 answer:
Andrew [12]3 years ago
7 0

i think it is c or b
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The second number in an ordered pie of numbers that corresponds to a point on a coordinate system is the
NNADVOKAT [17]

Answer:

The second number in an ordered pie of numbers that corresponds to a point on a coordinate system is the y<u>-value.</u>

3 0
3 years ago
Identify this sequence: 5, 15, 45, 135, …<br> Arithmetic<br> Geometric<br> Neither
user100 [1]

Answer:

5 * 2 is 10 + 5 and then 15 * 2 + 15 45 * 2 + 45

Step-by-step explanation:

times it by to add that number

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3 years ago
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Which of the following does the situation below best describe?
mestny [16]
The answer to the question is c
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2 years ago
"A rectangle has a height of 5 cm and its base is increasing at a rate" of 3/2 cm/min. When its area is 60 cm2, at what rate is
sukhopar [10]

Answer:

The diagonal is increasing at the rate of 119/104cm/min of the given rectangle.

Step-by-step explanation:

Dimensions of the rectangle

Height = 5cm

Rate of base = 3/2 cm/min

Area = 60cm^2

We know the area of a rectangle of given by = base* Height

b*h = 60

b*5 = 60

b = 12cm

Applying Pythagoras theorem while drawing a diagonal to the rectangle

  b^2 +h^2 =  D^2\\

 5^2 +12^2 = 13^2

so our diagonal will be 13cm  

Upon differentiating the area of the rectangle  we get

b*h = A=60cm^2

using  the chain rule of differentiation

h*db/dt + b*dh/dt  = 0

b*dh/dt = -h*db/dt

12*dh/dt = -5*3/2

dh/dt = -5/8 cm//min

so the height of the rectangle is decreasing at the rate of -5/8cm/min

now we have all the measurements we need

b = 12 , db/dt = 3/2cm/min

h = 5 , dh/dt = -5/8 cm/min

b^2 +h^2  = D^2

Upon differentiating we get

2b*db/dt + 2h*dh/dt = 2D*dD/dt

b*db/dt + h*dh/dt = D*dD/dt

12*3/2 + 5*(-5/8) = 13*dD/dt

18 -25/8 = 13*dD/dt

\frac{144-25}{8} = 13*dD/dt

dD/dt = \frac{119}{104} cm/min

Therefore the diagonal is increasing at the rate of 119/104cm/min of the given rectangle.

6 0
3 years ago
Miguel invests money in an account paying simple interest. He invests $170 and no money is added or removed from the investment.
stiv31 [10]

~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\dotfill & \$185.30\\ P=\textit{original amount deposited}\dotfill & \$170\\ r=rate\to r\%\to \frac{r}{100}\\ t=years\dotfill &1 \end{cases} \\\\\\ 185.30=170[1+(\frac{r}{100})(1)]\implies \cfrac{185.30}{170}=1+\cfrac{r}{100}\implies \cfrac{109}{100}=\cfrac{100+r}{100} \\\\\\ 109=100+r\implies \stackrel{\%}{9}=r

7 0
2 years ago
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