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andreev551 [17]
3 years ago
15

Rashad and Kendra were walking through the park and noticed several hummingbirds on a tree with yellow flowers. They wanted to k

now if the color yellow attracts hummingbirds more than other colors. Rashad and Kendra decided to test their hypothesis by doing an experiment in which they set up four hummingbird feeders with the same amount of food and placed them in locations only hummingbirds could reach. One feeder was yellow, one was red, one was blue, and one was clear. Each day for one week, Rashad and Kendra measured and recorded the amount of food left in each of the feeders. At the end of the experiment the red feeder had the least amount of food left in it. What conclusion should Rashad and Kendra reach?
Chemistry
2 answers:
bearhunter [10]3 years ago
8 0

Answer:

Yellow does not attract hummingbirds.

Explanation:

The most food wasn't taken out of the yellow feeders.

Sav [38]3 years ago
6 0

Answer:

The results failed to support the hypothesis that hummingbirds are most attracted to the color yellow.

Explanation:Cause i got it right

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What types of reactions are these 3 chemical equations?-
IceJOKER [234]

Answer:

*2Kl+Pb(NO3)2=PbI2+2KNO3: double replacement.

*2Al+3CuSO4=Al2(SO4)3+3Cu: single replacement.

*C2H5OH+3O2=2CO2+3H2O: combustion.

Explanation:

Hello there!

In this case, according to the required, it turns out necessary for us to recall the five types of reactions, combination, decomposition, single and double replacement and combustion as shown on the attached figure.

In such a way, since the first reaction follows the pattern AB+CD-->AD+CB we infer it is double replacement; the second reaction follows the patter A+BC-->AC+B and therefore it is single replacement; and the last one follows the pattern of combustion reaction due to the presence of CO2 and H2O on the products side.

Regards!

3 0
3 years ago
According to the law of conservation of matter, we know that the total number of atoms does not change in a chemical reaction an
Anna71 [15]

Answer:

the answer is second option. with 2 models

Explanation:

2H2 + O2 gives 2H2O

so there's two models

7 0
3 years ago
Read 2 more answers
the radius of the Sun is approximately 696,000 kilometers, while bacterial cells are as small as 1.9 × 10-4 millimeters. Express
Mazyrski [523]

Explanation;

Writing scientific notation :

  • Move the decimal to the left side until single digit of number remains before the decimal.
  • Then we will count the number of times we moved the decimal. Write this number as the exponential power of number '10'.
  • For Example: 2894.55=2.89455\times 10^{3}

Radius of the sun = 696,000.0 kilometer

1 km=10^3 m

Radius of the sun can also be written as = 6.96\times 10^{5} km=6.96\times 10^{5}\times 10^3 m=6.96\times 10^{8} meter

Size of bacterial cell = 1.9\times 10^{-4} millimeter

1 mm=1\times 10^{-3} m

Size of bacterial cell can also be written as = 1.9\times 10^{-4}\times 10^{-3} m=1.9\times 10^{-7} meter

4 0
3 years ago
A sealed, expandable container is initially at 2.000 L and 25°C. To what temperature must it be changed to have a volume of 6.00
balandron [24]

Answer:

The new temperature is 894 K or 621 °C

Explanation:

Step 1: Data given

Initial volume of the container = 2.000L

Initial temperature = 25.0 °C = 298 K

Volume increased to 6.00 L

Step 2: Calculate the new temperature

V1/T1 = V2/T2

⇒with V1 = the initial volume = 2.00L

⇒with T1 = the initial temperature = 25 °C = 298 K

⇒with V2 = the increased volume 6.00 L

⇒with T2 = the new temperature

2.00 L / 298 K = 6.00 L / T2

T2 = 894 K = 621 °C

The new temperature is 894 K or 621 °C

4 0
4 years ago
An ideal gas in a closed container initially has a volume V and Temperature T the final tempera is 5/4T and the final pressure i
Anettt [7]

Answer:

V_2 = \frac{5V}{8}

Explanation:

I am assuming you are saying what is the final volume of the gas

Known :

Initial volume (V1) = V

Initial temperature (T1) = T

Final temperature (T2) = 5/4 T

Initial pressure (P1) = P

Final pressure (P2) = 2P

<u>Wanted: Final volume (V2)</u>

<u />

<u />\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}\\\frac{PV}{T} = \frac{(2P)V_2}{(5/4)T}\\\frac{V}{1} = \frac{(2)V_2}{5/4}\\5/4V = 2V_2\\\\V_2 = \frac{5V}{8}

5 0
2 years ago
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