Answer:
Follows are the solution:
Explanation:
A + B = C
Its response decreases over time as well as consumption of a reactants.
r = -kAB
during response A convert into 2x while B convert into x to form 3x of C
let's y = C
y = 3x
Still not converted sum of reaction
for A: 100 - 2x
for B: 50 - x
Shift of x over time
Integration of x as regards t
![\frac{1}{[(100 - 2x)(50 - x)]} dx = -k dt\\\\\frac{1}{2[(50 - x)(50 - x)]} dx = -k dt\\\\\ integral\ \frac{1}{2[(50 - x)^2]} dx =\ integral [-k ] \ dt\\\\\frac{-1}{[100-2x]} = -kt + D \\\\](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5B%28100%20-%202x%29%2850%20-%20x%29%5D%7D%20dx%20%3D%20-k%20dt%5C%5C%5C%5C%5Cfrac%7B1%7D%7B2%5B%2850%20-%20x%29%2850%20-%20x%29%5D%7D%20dx%20%3D%20-k%20dt%5C%5C%5C%5C%5C%20integral%5C%20%20%5Cfrac%7B1%7D%7B2%5B%2850%20-%20x%29%5E2%5D%7D%20dx%20%3D%5C%20integral%20%5B-k%20%5D%20%5C%20dt%5C%5C%5C%5C%5Cfrac%7B-1%7D%7B%5B100-2x%5D%7D%20%3D%20-kt%20%2B%20D%20%5C%5C%5C%5C)
D is the constant of integration
initial conditions: t = 0, x = 0
![\frac{-1}{[100-2x]} = -kt + D \\\\\frac{ -1}{[100]} = 0 + D\\\\D= \frac{-1}{100}\\\\](https://tex.z-dn.net/?f=%5Cfrac%7B-1%7D%7B%5B100-2x%5D%7D%20%3D%20-kt%20%2B%20D%20%20%20%5C%5C%5C%5C%5Cfrac%7B%20-1%7D%7B%5B100%5D%7D%20%3D%200%20%2B%20D%5C%5C%5C%5CD%3D%20%5Cfrac%7B-1%7D%7B100%7D%5C%5C%5C%5C)
hence we get:
![\frac{-1}{[100-2x]}= -kt -\frac{1}{100}\\\\or \\\\ \frac{1}{(100-2x)} = kt + \frac{1}{100}](https://tex.z-dn.net/?f=%5Cfrac%7B-1%7D%7B%5B100-2x%5D%7D%3D%20-kt%20-%5Cfrac%7B1%7D%7B100%7D%5C%5C%5C%5Cor%20%5C%5C%5C%5C%20%5Cfrac%7B1%7D%7B%28100-2x%29%7D%20%3D%20kt%20%2B%20%5Cfrac%7B1%7D%7B100%7D)
after t = 7 minutes , 
Insert the above value x into 
equation 
to get k.
therefore plugging in the equation the above value of k
Let y = C
, calculate C:
y = 3x
amount of C formed in 28 mins
plug t = 28
therefore amount of C formed in 28 minutes is = 3x = 144.78 grams
C:
y= 136.5 =137
Your answer would be "Chemical Change"
Answer:
Energy of photon is 34.45 ×10⁻¹⁹ J.
Explanation:
Given data:
Frequency of photon = 5.2×10¹⁵ s⁻¹
Plancks constant = 6.626×10⁻³⁴ Js
Energy of photon = ?
Solution:
Formula:
E = h.f
by putting values,
E = 6.626×10⁻³⁴ Js × 5.2×10¹⁵ s⁻¹
E = 34.45 ×10⁻¹⁹ J
Thus, energy of photon is 34.45 ×10⁻¹⁹ J.
Answer:
Diamond - E
Sugar- C
Milk - M
Iron- E
Air- M
Sulfuric Acid- C
Gasoline - M
Electricity- X
Krypton- E
Bismuth - E
Uranium - E
Kool-Aid -M
Water - C
Alcohol - C
Pail of Garbage - M
Ammonia - C
Salt - C
Energy - X
Gold - E
Wood - M
Bronze - M
Ink - M
Pizza - M
Dry Ice - C
Baking Soda - C
Explanation:
An element is the smallest part of a substance that is capable of independent existence. An element cannot be broken down into any other substance. Krypton, Bismuth etc are all elements.
A compound is a combination of two or more elements which are chemically combined together e.g NH3, CO2 etc.
A mixture is any combination of substances that are not chemically combined together. E.g Pizza, milk etc
Answer: 1) absorbed
Explanation:
As a chemical bond is formed either by transfer of electrons or sharing of electrons, in order to break the forces of attraction among atoms, energy must be absorbed.
Energy is produced or released when a chemical bond is formed.
Energy is never destroyed, it converts from one form to another.
