1.regulating ph
2.heating
3.adding some oppositely charged colloids
Explanation:
Since this is an equilibrium problem, we apply le chatelier principle. This principle states that whenever a system at equilibrium is disturbed due to change in several factors, it would move in a way to annul such change.
C2H4(g) + Cl2 ⇔ 2C2H4Cl2(g)
When the concentration of C2H4 is increased, there is more reactant sin the system. In order to annul this change, the equilibrium position will shift to the right favoring product formation.
When the concentration of C2H4Cl2 is increased, there is more product in the system. To annul this change, the equilibrium position will shift to the left, favoring reactant formation.
Answer:
The answer is "2.5 mole"
Explanation:
The reaction for producing 
can be defined as follows:
Reaction:
According to the above reaction, to produce 2 moles of we need 1 mole of nitrogen:
So, according to the question to produce 5.0 mole the required 
:
To produce 5.0 mole we need 2.5 mole
A mole is equal to 6.02x10^23, so one mole of H2O has 6.02x10^23 water molecules. To get how many of them are in 6 moles you need to multiple it by six:
(6.02x10^23)x6= 3.612x10^24
So, there’s 3.612x10^24 water molecules in 6 moles of water
