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2 years ago

( 5+ y) + 6x when x = 10 and y =7

Mathematics

2 answers:

gladu [14]2 years ago

7 0

Answer:

Step-by-step explanation:

( 5+ y) + 6x

Let x = 10 and y = 7

( 5+ 7) + 6*10

12 + 60

Alina [70]2 years ago

3 0

Answer:

Step-by-step explanation:

sub in your given numbers

do PEMDAS

Perathasieis (5 + 10) = 50

6(7) = 42

add 50 + 42

you get 90

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A wallet contains five $10 bills, three $5 bills, six $1 bills, and no larger denominations. If bills are randomly selected one-

Black_prince [1.1K]

Answer:

$\frac{4}{21}$

Step-by-step explanation:

Another way of phrasing this question is this; if only two bills are selected without replacement, what is the probability that at one of the two bills will be a $10 bill:

P(One $10 bill) = P(picking a $10 bill first then another type) + (picking another

type then a $10 bill)

= $\frac{5}{15}*\frac{10}{14}+\frac{10}{15} *\frac{5}{14} = \frac{4}{21}$

6 0

3 years ago

Which ordered pairs are in a proportional relationship with (0.2, 0.3)?

MAXImum [283]

Answer:

C and E

Step-by-step explanation:

We are given that

$x_1=0.2,y_1=0.3$

$\frac{y}{x}=\frac{0.3}{0.2}=\frac{3}{2}$

$k=\frac{y}{x}=\frac{3}{2}$

A. $x_2=1.2,y_2=2.3$

$\frac{y_2}{x_2}=\frac{2.3}{1.2}=\frac{23}{12}\neq=\frac{3}{2}$

Hence, it is not in proportional relationship with (0.2,0.3)

B.(2.7,4.3)

$x_3=2.7,y_3=4.3$

$\frac{y_3}{x_3}=\frac{4.3}{2.7}=\frac{43}{27}\neq\frac{3}{2}$

Hence, it is not in proportional relationship with (0.2,0.3).

C.(3.2,4.8)

$x_4=3.2,y_4=4.8$

$\frac{y_4}{x_4}=\frac{4.8}{3.2}=\frac{3}{2}$

Hence, the ordered pair (3.2,4.8) are in a proportional relationship with (0.2,0.3).

D.(3.5,5.3)

$\frac{y_5}{x_5}=\frac{5.3}{3.5}=\frac{53}{35}\neq \frac{3}{2}$

Hence, the ordered pair (3.5,5.3) are not in a proportional relationship with (0.2,0.3).

E.(5.2,7.8)

$\frac{y_6}{x_6}=\frac{7.8}{5.2}=\frac{3}{2}$

Hence, the ordered pair (5.2,7.8) are in a proportional relationship with (0.2,0.3).

4 0

2 years ago

Find the solution to the system of equations below.

leva [86]

Answer:

the answer is c.(3,-3)

Step-by-step explanation:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

3 0

2 years ago

Question 6 (1 point)

Alika [10]

59 cans ... she counting up by 5s so multiply 5 x 10

6 0

2 years ago

Show that the sum of the first 2n natural numbers is n(2n+1)

Leokris [45]

Answer:

This sum is the sum of an arithmetic sequence. There is a formula for the sum of an arithmetic sequence which can be looked up or derived by a variety of means.

A nice approach for this sequence is the following. Notice that the sum of first and last number in the sequence is the same as the sum of the second and second last, and also the same as the sum of the third and third last, and so on.

There are n of these pairs. So the desired sum is n x (first number + last number). But the first number is 1 and the last on is 2n. Thus the desired sum is n(1 + 2n).

Hope this helps!!

Mark Brainleast!!!!!!!!!!!

7 0

2 years ago

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( 5+ y) + 6x when x = 10 and y =7​

( 5+ y) + 6x when x = 10 and y =7