At what temperature would one mole of molecular nitrogen (N_2) have 7.0 × 10^3 J of translational kinetic energy (total internal
energy)? Note: the atomic mass of N is 14 g/mol.
1 answer:
Answer:
T = 561.3K
Explanation:
The translational kinetic energy of a gas such as nitrogen is obtained using the formula:
K = 3/2 * n * R * T
<em>Where n are moles of gases (1mole of N₂), R is gas constant (8.314J/molK)and T is absolute temperature (in K)</em>
If the translational energy of the gas is 7.0x10³J:
7.0x10³J = 3/2 * 1 mole * 8.314J/molK * T
<h3>T = 561.3K</h3>
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The answer to your question is C.)
Answer:
126 grams
Explanation:
What is the mass of two moles of HNO3?
H = 1g/mole = 1+
N = 14g/mole = 3-
O = 16g/mole = 2-
HNO3 = 63g/mole
P=m/V
m=40.24 g
V=50.0 mL=50.0 cm³
p=40.24/50.0=0.8048 g/cm³
Use Socratic or quiz let it help
The percent yield : 73.5%
<h3>Further explanation</h3>
Given
Reaction
C+2H₂⇒CH₄
Required
The percent yield
Solution
mol of Carbon(as a limiting reactant) :
mol CH₄ based on C, and from equation mol ratio C : CH₄, so mol CH₄ = 8.3
Mass of Methane(theoretical yield) :
