Question

A solution of NaCl has a concentration of 1.50 M. The density of the solution is 1.06 g/mL. What is the concentration solution by percent in mass?

Answer 1

Answer:

8.27% on edge

Explanation:

Answer 2

Answer:

The concentration solution by percent in mass is 8.28%

Explanation:

Molarity is moles of solute present in 1L of its solution .

Hence the formula is  

$\left.\text {Molarity}=\frac{\text {moles of solute}}{\text {Volume of solution in } L} \text { (unit is } \frac{\text { mol }}{L} \text { or } M\right)=\frac{1.50 \mathrm{mol}}{1 \mathrm{L}}$

Let us convert the numerator and the denominator into mass in g

Numerator :                                  

$mass = moles \times molar mass\\\\ =1.50 \mathrm{mol} \times 58.5 \frac{g}{\text { mol }}=87.75 \mathrm{g} (solute)$

Denominator :                        

$\begin{aligned} \text {mass} &=\text { density } \times \text {volume}=\frac{1.06 \mathrm{g}}{1 \mathrm{ml}} \times 1 \mathrm{L} \\\\ &=\frac{1.06 \mathrm{g}}{1 \mathrm{ml}} \times 1000 \mathrm{ml}=1060 \mathrm{g} \end{aligned}$

The formula to find mass percentage is

$\% mass =\frac{\text { mass of solute }}{\text { mass of solution }} \times 100 \%$

$\% mass of \mathrm{NaCl}=\frac{\text { mass of solute }}{\text { mass of solution }} \times 100 \%$

$=\frac{87.75 g}{1060 g} \times 100 \%$

=8.28% (Answer)