1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sashaice [31]
3 years ago
15

A solution of NaCl has a concentration of 1.50 M. The density of the solution is 1.06 g/mL. What is the concentration solution b

y percent in mass?
Chemistry
2 answers:
Alina [70]3 years ago
8 0

Answer:

8.27% on edge

Explanation:

gavmur [86]3 years ago
7 0

<u>Answer:</u>

<em>The concentration solution by percent in mass is 8.28%</em>

<u>Explanation:</u>

Molarity is moles of solute present in 1L of its solution .

Hence the formula is  

$\left.\text {Molarity}=\frac{\text {moles of solute}}{\text {Volume of solution in } L} \text { (unit is } \frac{\text { mol }}{L} \text { or } M\right)=\frac{1.50 \mathrm{mol}}{1 \mathrm{L}}$

Let us convert the numerator and the denominator into mass in g

Numerator :                                  

mass $=$ moles $\times$ molar mass\\\\$=1.50 \mathrm{mol} \times 58.5 \frac{g}{\text { mol }}=87.75 \mathrm{g}$ (solute)

Denominator :                        

$\begin{aligned} \text {mass} &=\text { density } \times \text {volume}=\frac{1.06 \mathrm{g}}{1 \mathrm{ml}} \times 1 \mathrm{L} \\\\ &=\frac{1.06 \mathrm{g}}{1 \mathrm{ml}} \times 1000 \mathrm{ml}=1060 \mathrm{g} \end{aligned}$

The formula to find mass percentage is

$\%$ mass $=\frac{\text { mass of solute }}{\text { mass of solution }} \times 100 \%$

$\%$ mass of $\mathrm{NaCl}=\frac{\text { mass of solute }}{\text { mass of solution }} \times 100 \%$

$=\frac{87.75 g}{1060 g} \times 100 \%$\\

=8.28% (Answer)

You might be interested in
Explain what happens to the light ray when above and below the line are both water
IceJOKER [234]

<>"Refraction is the bending of the path of a light wave as it passes from one material into another material. The refraction occurs at the boundary and is caused by a change in the speed of the light wave upon crossing the boundary. The tendency of a ray of light to bend one direction or another is dependent upon whether the light wave speeds up or slows down upon crossing the boundary. The speed of a light wave is dependent upon the optical density of the material through which it moves. For this reason, the direction that the path of a light wave bends depends on whether the light wave is traveling from a more dense (slow) medium to a less dense (fast) medium or from a less dense medium to a more dense medium. In this part of Lesson 1, we will investigate this topic of the direction of bending of a light wave.    

Predicting the Direction of Bending

Recall the Marching Soldiers analogy discussed earlier in this lesson. The analogy served as a model for understanding the boundary behavior of light waves. As discussed, the analogy is often illustrated in a Physics classroom by a student demonstration. In the demonstration, a line of students (representing a light wave) marches towards a masking tape (representing the boundary) and slows down upon crossing the boundary (representative of entering a new medium). The direction of the line of students changes upon crossing the boundary. The diagram below depicts this change in direction for a line of students who slow down upon crossing the boundary.

On the diagram, the direction of the students is represented by two arrows known as rays. The direction of the students as they approach the boundary is represented by an incident ray (drawn in blue). And the direction of the students after they cross the boundary is represented by a refracted ray (drawn in red). Since the students change direction (i.e., refract), the incident ray and the refracted ray do not point in the same direction. Also, note that a perpendicular line is drawn to the boundary at the point where the incident ray strikes the boundary (i.e., masking tape). A line drawn perpendicular to the boundary at the point of incidence is known as a normal line. Observe that the refracted ray lies closer to the normal line than the incident ray does. In such an instance as this, we would say that the path of the students has bent towards the normal. We can extend this analogy to light and conclude that:

Light Traveling from a Fast to a Slow Medium

If a ray of light passes across the boundary from a material in which it travels fast into a material in which travels slower, then the light ray will bend towards the normal line.

The above principle applies to light passing from a material in which it travels fast across a boundary and into a material in which it travels slowly. But what if light wave does the opposite? What if a light wave passes from a material in which it travels slowly across a boundary and into a material in which it travels fast? The answer to this question can be answered if we reconsider the Marching Soldier analogy. Now suppose that the each individual student in the train of students speeds up once they cross the masking tape. The first student to reach the boundary will speed up and pull ahead of the other students. When the second student reaches the boundary, he/she will also speed up and pull ahead of the other students who have not yet reached the boundary. This continues for each consecutive student, causing the line of students to now be traveling in a direction further from the normal. This is depicted in the diagram below.

"<>

4 0
3 years ago
What is the relationship between the oxygen cycle and the carbon cycle
Ganezh [65]
Photosynthesis. Because the plants give off oxygen as a waste product. Carbon dioxide then moves from the air into the leaves of plants through tiny openings in the plants leaves.
5 0
3 years ago
Read 2 more answers
Phosphodiesterase functions Select one: a. as a membrane-bound receptor molecule. b. to inactivate cyclic AMP. c. to attach phos
ikadub [295]
Cyclic nucleotides cAMP and cGMP are part of almost all major cellular signaling pathways. Phosphodiesterases (PDEs) are enzymes that regulate the intracellular levels of cAMP and cGMP. Protein kinase A or cAMP-dependent protein kinase mediates most cAMP effects in the cell. Over the last 25 years, various components of this group of molecules have been involved in human diseases, both genetic and acquired. Lately, the PDEs attract more attention. The pharmacological exploitation of the PDE’s ability to regulate cGMP and cAMP, and through them, a variety of signaling pathways, has led to a number of new drugs for diverse applications from the treatment of erectile dysfunction to heart failure, asthma, and chronic obstructive pulmonary disease. We present the abstracts (available online) and selected articles from the proceedings of a meeting that took place at the National Institutes of Health (NIH), Bethesda, MD, June 8–10, 2011.

8 0
3 years ago
Which of the following is not a reason for extinction?
Rashid [163]

Answer:

the ability to breed successfully

Explanation:

3 0
3 years ago
Read 2 more answers
Pinky put her wet clothes inside the room for drying. But her mom told her to put it under the sun. Give reason why her mom told
bulgar [2K]

so it doesn't get smaller

5 0
2 years ago
Other questions:
  • Characteristic of a chemical compound
    13·1 answer
  • Please help me asap​
    13·1 answer
  • Spell out full name of compound
    13·2 answers
  • I need this ASAP! Thank you!
    10·2 answers
  • At T = 250 °C the reaction PCl5(g) PCl3(g) + Cl2(g) has an equilibrium constant in terms of pressures Kp = 2.15. (a) Suppose the
    13·1 answer
  • Safety is a concern around electronic equipment of all types. What particular safety hazard may exist A. Laser light B. High vol
    11·1 answer
  • A 31.25 mL aliquot of weak base that has a concentration of 0.683 M will be titrated with 0.434 M HCl. Calculate the pH of of th
    9·1 answer
  • Which of the following is the ground state electrons configuration of the F ion
    5·1 answer
  • Plz help me with this pt.3
    14·1 answer
  • Hi! I'm hoping someone can help me with this please thank you XD
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!