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ankoles [38]
3 years ago
14

An atom of uranium-238 undergoes radioactive decay to form an atom of thorium-234. Which type of nuclear decay has occurred?

Chemistry
1 answer:
WINSTONCH [101]3 years ago
5 0

Answer:-

Alpha decay

Explanation:-

Uranium 238 has atomic number 92 and mass number 238.

Thorium 234 has atomic number 90 and mass number 234.

So, the change in atomic number as uranium 238 disintegrates into thorium234 = 92 – 90 = 2

So, the change in mass number as uranium 238 disintegrates into thorium234= 238 – 234 = 4

We know that when an alpha particle is emitted, the mass number decreases by 4 and the atomic number decreases by 2.

So when an atom of uranium 238 undergoes radioactive decay to form an atom of thorium-234, alpha decay has occurred.

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Is H2CO3 an Arrhenius acid?
Korolek [52]
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6 0
3 years ago
A beaker with 155 mL of an acetic acid buffer with a pH of 5.000 is sitting on a benchtop. The total molarity of acid and conjug
OverLord2011 [107]

Answer:

ΔpH = 0.296

Explanation:

The equilibrium of acetic acid (CH₃COOH) in water is:

CH₃COOH ⇄ CH₃COO⁻ + H⁺

Henderson-Hasselbalch formula to find pH in a buffer is:

pH = pKa + log₁₀ [CH₃COO⁻] / [CH₃COOH]

Replacing with known values:

5.000 = 4.740 + log₁₀ [CH₃COO⁻] / [CH₃COOH]

0.260 =  log₁₀ [CH₃COO⁻] / [CH₃COOH]

1.820 = [CH₃COO⁻] / [CH₃COOH] <em>(1)</em>

As total molarity of buffer is 0.100M:

[CH₃COO⁻] + [CH₃COOH] = 0.100M <em>(2)</em>

Replacing (2) in (1):

1.820 = 0.100M - [CH₃COOH] / [CH₃COOH]

1.820[CH₃COOH] = 0.100M - [CH₃COOH]

2.820[CH₃COOH] = 0.100M

[CH₃COOH] = 0.100M / 2.820

[CH₃COOH] = <em>0.035M</em>

Thus: [CH₃COO⁻] = 0.100M - 0.035M = <em>0.065M</em>

5.40 mL of a 0.490 M HCl are:

0.0054L × (0.490mol / L) = 2.646x10⁻³ moles HCl.

Moles of CH₃COO⁻ are: 0.155L × (0.065mol / L) = 0.0101 moles

HCl reacts with CH₃COO⁻ thus:

HCl + CH₃COO⁻ → CH₃COOH

After reaction, moles of CH₃COO⁻ are:

0.0101 moles - 2.646x10⁻³ moles = <em>7.429x10⁻³ moles of CH₃COO⁻</em>

<em />

Moles of CH₃COOH  before reaction are: 0.155L × (0.035mol / L) = 5.425x10⁻³ moles of CH₃COOH. As reaction produce 2.646x10⁻³ moles of CH₃COOH, final moles are:

5.425x10⁻³ moles +  2.646x10⁻³ moles = <em>8.071x10⁻³ moles of CH₃COOH</em>. Replacing these values in Henderson-Hasselbalch formula:

pH = 4.740 + log₁₀ [7.429x10⁻³ moles] / [8.071x10⁻³ moles]

pH = 4.704

As initial pH was 5.000, change in pH is:

ΔpH = 5.000 - 4.740 = <em>0.296</em>

4 0
3 years ago
The rate law for 2NO(g) + O₂(g) → 2NO₂(g) is rate = is rate k[NO]²[O₂]. is rateIn addition to the mechanism in the text (p. 709)
KonstantinChe [14]

The rate law depicts the effect of concentration on reaction rate. Second mechanism 2NO(g) ⇄ N₂O₂(g) [fast], N₂O₂(g) + O₂(g) → 2NO₂(g) [slow] is most reasonable. Thus, option b is correct.

<h3>What is rate law?</h3>

Rate law and equation give the rate at which the reaction takes place under the influence of the concentration of the reactants. The balanced chemical reaction is given as,

2NO(g) + O₂(g) → 2NO₂(g)

The rate of the equation is given as,

rate = k [NO]² [O₂]  

In a multi-step chemical reaction, the slowest step is the rate-determining step. The second mechanism is given as,

2NO (g) → N₂O₂ (g) [fast]

N₂O₂(g) +O₂(g) → 2NO₂ (g) [slow]

Rate is given as,

rate = k [N₂O₂] [O₂]

Therefore, option b. the second mechanism is the most reasonable.

Learn more about rate law, here:

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5 0
2 years ago
There are many advantages to using nuclear power to generate electricity. There are also many disadvantages. Choose all of the a
elena55 [62]

Answer:

abc

Explanation:

6 0
3 years ago
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A student was asked to determine the densities of the four metals listed. The student was asked to determine the density of an u
Iteru [2.4K]

Answer:

D is correct

Explanation:

because

we know that

density of lead is 11.36 g/cm3

and

density of tin is 7.31 g/cm3

so..

density of alloy by mixing 50/50

=(11.36+7.31)/2 g/cm3

=18.67/2 g/cm3

=9.33 g/cm3

5 0
3 years ago
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