On the left (reactant) side you have 6 N-H bonds and 1 Cl-Cl bond
<span>On the right (product) side you have 4 N-H bonds, 1 N-N bond and 2 H-Cl bonds </span>
<span>Add up the bond energies for each side (multiplying by the number of bonds) and calculate the difference for your ΔHº</span>
Explanation:
row of the periodic table called periods
and group
Answer:
6792.1 g
Explanation:
Dimensional analysis:
376.92 mol H2 * (2 mol h2o / 2 mol h2) * (18.02g h2o / 1 mol h2o)
6792.1 g
Answer:
4.867 L of ammonia
Explanation:
Using Haber's process to form ammonia using Nitrogen and hydrogen, the equation is :
N₂ + 3H₂ → 2NH₃
Here, 3 moles of hydrogen gas gives 2 moles of ammonia.
1 mole of any substance occupies 22.4L at STP
So, 3 x 22.4L of hydrogen gives 2 x 22.4 L of ammonia
Then 7.3 L of hydrogen will give:
=
=
= 4.867 L of ammonia