F = kq2 / r2
q = ne
F = k(ne)2 / r2
n = âš(r2F / ke2) = (r/e) âš(F/k)
k = 9 x 109 Nm2/C2
e = 1.6 x 10-19 C
n = [(4.2 x 10-10) / (1.6 x 10-19)] âš[(5.2 x 10-9) / (9 x 109)] â‰… 1.995 â‰… 2

7 0

3 years ago

Given that the image below is not drawn to

Natali [406]

Answer:

what image i dont see an image

Step-by-step explanation:

4 0

3 years ago

a philanthropist deposits 2,000$, in a trust fund that pays 6.0%interest , compunded continuously. The balance given to the coll

maw [93]

Answer:

$6414

Step-by-step explanation:

Step one

given

Principal=$2,000

rate= 6%= 0.06

Time= 20 years

Required

The final amount

Step two:

The compound interest formula is

A= P(1+r)^t

substituting we have

$A=2000(1+0.06)^2^0\\\\ A= 2000(1.06)^2^0\\\\ A=2000*3.207\\\\A=6414$

The amount given to the college is $6414

7 0

3 years ago