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notka56 [123]
3 years ago
10

Pls I need the Answer Q9

Mathematics
1 answer:
atroni [7]3 years ago
7 0

I believe you take the derivative and then set to zero.

4x + 8

set to zero:

4x + 8 = 0

x = -2

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wo balls are chosen randomly from an um containing 8 white, 4 black,and 2 orange balls. Suppose that we win $2 for each black ba
umka21 [38]

Answer:

The probability distribution is shown below.

Step-by-step explanation:

The urn consists of 8 white (<em>W</em>), 4 black (<em>B</em>) and 2 orange (<em>O</em>) balls.

The winning and losing criteria are:

  • Win $2 for each black ball selected.
  • Lose $1 for each white ball selected.

There are 8 + 4 + 2 = 14 balls in the urn.

The number of ways to select two balls is, {14\choose 2}=91 ways.

The distribution of amount won or lost is as follows:

Outcomes: WW  WO  WB  BB  BO  OO

X:                 -2      -1      1      4     2      0

Compute the probability of selecting 2 white balls as follows:

The number of ways to select 2 white balls is, {8\choose 2}=28 ways.

The probability of WW is,

P(WW)=\frac{n(WW)}{N}=\frac{28}{91}=0.3077

Compute the probability of selecting 1 white ball and 1 orange ball as follows:

The number of ways to select 1 white ball and 1 orange ball is, {8\choose 1}\times {2\choose 1}=16 ways.

The probability of WO is,

P(WO)=\frac{n(WO)}{N}=\frac{16}{91}=0.1758

Compute the probability of selecting 1 white ball and 1 black ball as follows:

The number of ways to select 1 white ball and 1 black ball is, {8\choose 1}\times {4\choose 1}=32 ways.

The probability of WB is,

P(WB)=\frac{n(WB)}{N}=\frac{32}{91}=0.3516

Compute the probability of selecting 2 black balls as follows:

The number of ways to select 2 black balls is, {4\choose 2}=6 ways.

The probability of BB is,

P(BB)=\frac{n(BB)}{N}=\frac{6}{91}=0.0659

Compute the probability of selecting 1 black ball and 1 orange ball as follows:

The number of ways to select 1 black ball and 1 orange ball is, {4\choose 1}\times {2\choose 1}=8 ways.

The probability of BO is,

P(BO)=\frac{n(BO)}{N}=\frac{8}{91}=0.0879

Compute the probability of selecting 2 orange balls as follows:

The number of ways to select 2 orange balls is, {2\choose 2}=1 ways.

The probability of OO is,

P(OO)=\frac{n(OO)}{N}=\frac{1}{91}=0.0110

The probability distribution of <em>X</em> is:

Outcomes:    WW     WO        WB         BB        BO         OO

X:                    -2          -1            1            4            2            0

P (X):           0.3077  0.1758  0.3516  0.0659  0.0879  0.0110

3 0
4 years ago
Find the unit price for each trail mix. cost is $6.00 and weight 3/4Lb
iragen [17]
6/ 3/4
6(4/3)
= 8

The answer is 8. 
5 0
4 years ago
Mike practices the cello every 5 days and the piano every 13 days. Mike practiced both the cello and the piano today. How many d
Rus_ich [418]

Answer:

65 days.

Step-by-step explanation:

because 13 multiplied 5 is 65 and 5 multiplied by 13 is also 65.

7 0
3 years ago
Rebecca and Jago are proving the Pythagorean Theorem for a triangle. They arrange four congruent right triangles with sides
iren [92.7K]

I'm sure the answer is B if it's not B it's A trust

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2 years ago
Six times a number is greater than 20 more than that number. What are the possible values of that number?
densk [106]

Answer:

x>4

Step-by-step explanation:

first take 6*x (x is for a number) and you have 20+x. So put the inequality together and you get 6x>20+x

so then subtract x from both sides and you get 5x>20 then divide by 5 to isolate x and you get x>4.

so the possible value is any number greater than 4.

3 0
3 years ago
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