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dolphi86 [110]
2 years ago
8

Simplify the expression z^2-z(z+3)+3z

Mathematics
2 answers:
Alisiya [41]2 years ago
5 0
<span>z^2-z(z+3)+3z

z^2 - z^2 - 3z + 3z

0 + 0

0

</span><span>z^2-z(z+3)+3z = 0</span>
fiasKO [112]2 years ago
3 0
z^2-z(z+3)+3z 

z^2-z^2-3z+3z&#10; 

-3z+3z
 
0  \text{Solution}

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If J is the centroid of cde, de=52, fc=15, he=14, find each missing measure
const2013 [10]

Answer:

DG = 26

GE = 26

DF = 15

CH = 14

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Step-by-step explanation:

The figure has been attached, to complement the question.

DE = 52

FC = 15

HE = 14

Given that J is the centroid, it means that J divides sides CD, DE and CE into two equal parts respectively and as such the following relationship exist:

DF = FC

CH = HE

DG = GE

Solving (a): DG

If DG = GE, then

DE = DG + GE

DE = DG + DG

DE = 2DG

Make DG the subject

DG = \frac{1}{2}DE

Substitute 52 for DE

DG = \frac{1}{2} * 52

DG = 26

Solving (b): GE

If DG = GE, then

GE = DG

GE = 26

Solving (c): DF

DF = FC

So:

DF = 15

Solving (d): CH

CH = HE

CH = 14

Solving (e): CE

If CH = HE, then

CE = CH + HE

CE = 14 + 14

CE = 28

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