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asambeis [7]
3 years ago
7

You have a pulley 10.4 cm in diameter and with a mass of 2.3 kg. You get to wondering whether the pulley is uniform. That is, is

the mass evenly distributed, or is it concentrated toward the center or the rim? To find out, you hang the pulley on a hook, wrap a string around it several times, and suspend your 1.7 kg physics book 1.0 m above the floor. With your stopwatch, you can find that it takes 0.64 s for your book to hit the floor. Use g=9.8 m/s2.
Physics
1 answer:
madreJ [45]3 years ago
4 0

Answer:

Explanation:

Given

Diameter of Pulley=10.4 cm

mass of Pulley(m)=2.3 kg

mass of book(m_0)=1.7 kg

height(h)=1 m

time taken=0.64 s

h=ut+frac{at^2}{2}

1=0+\frac{a(0.64)^2}{2}

a=4.88 m/s^2and [tex]a=\alpha r

where \alphais angular acceleration of pulley

4.88=\alpha \times 5.2\times 10^{-2}

\alpha =93.84 rad/s^2

And Tension in Rope

T=m(g-a)

T=1.7\times (9.8-4.88)

T=8.364 N

and Tension will provide Torque

T\times r=I\cdot \alpha

8.364\times 5.2\times 10^{-2}=I\times 93.84

I=0.463\times 10^{-2} kg-m^2

I_{original}=\frac{mr^2}{2}=0.31\times 10^{-2}kg-m^2

Thus mass is uniformly distributed or some more towards periphery of Pulley

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Answer: Taking into account sound is a wave, we can use the information of the displacement (generally given as a graph) to find the wavelength and frequency, then we can calculate the speed with the formula of the speed of a wave.

Explanation:

If we have the displacement graph of the sound wave, we can find its amplitude, its wavelength and period (which is the inverse of frequency).

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a 64kg skateboarder on a 2.0kg skateboard is on top of a ramp with a vertical height of 5.0 m what is the skateboarders maximum
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3 years ago
An LC circuit consists of a 3.4-µF capacitor and a coil with a self-inductance 0.080 H and no appreciable resistance. At t = 0 t
alexira [117]

Answer

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after time T/4 current reach maximum

 t = \dfrac{T}{4}

 t = \dfrac{2\pi\sqrt{LC}}{4}

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3 years ago
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Paha777 [63]

Answer:

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When a negatively charged rod is held above the top of left sphere, the rod will attract positive charges and repel negative charges. As the sphere are initially touching each other so positive charges from the both spheres will moves toward the rod. When we separate the spheres positive charges from right sphere have already moved toward the rod i.e. left sphere, creating a deficiency of positive charges in the right sphere and excessiveness of positive charges in left sphere , hence the right sphere will remain negatively charged and left sphere will remain positively charged.

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