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ohaa [14]
2 years ago
11

A 48 N force accelerates a block at 6 m/s/s. What is the mass of the block?

Physics
1 answer:
tatuchka [14]2 years ago
6 0

Answer:8

Explanation:

m=f/a

48/6=8

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A rock is being twirled in a circle on the end of a string. The string provides the centripetal force needed to keep the ball mo
KonstantinChe [14]

Answer:

No

Explanation:

The force of tension exerted by the string on the rock acts as centripetal force, so its direction is always towards the centre of the circle.

However, the direction of motion of the rock is always tangential to the circle: this means that the force is always perpendicular to the direction of motion of the rock.

As we know, the work done by a force on an object is

W=Fd cos \theta

where

F is the magnitude of the force

d is the displacement of the object

\theta is the angle between the force and the displacement

In this situation, F and d are perpendicular, so \theta=90^{\circ}, therefore cos \theta = 0 and the work done is zero:

W=0

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2 years ago
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Arada [10]
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3 years ago
Change the following data into scientific notation.<br><br> 5 000 000 km
RoseWind [281]
To find out scientific notation, you want to make sure that number is less than 10. So do 5.000000, you don't rally need the zeros but I just want to make my point. So use 10^x meaning ten the whatever power adds zeros like 5.000000x10^6 meaning it is increasing it by six zeros moving it out of the decimals and letting become 5,000,000. 
8 0
3 years ago
A bell rings at a frequency of 75hz on a warm 25 degree evening. calculate the...
allochka39001 [22]

Answer:

Explanation:

We need 2 different equations for this problem: first the velocity of sound equation, then the frequency of the sound equation.

The velocity of sound is found in:

v = 331.5 + .606T

We need to find that first in order to fill it into the frequency equation which is

f=\frac{v}{\lambda} where v is the velocity we will find the part a, f is frequency and lambda is the wavelength. Starting with the velocity of the sound:

v = 331.5 + .606(25) and

v = 331.5 + 15 and rounding correctly using the rules for sig fig when adding:

v = 347 m/s

Filling that into the frequency equation:

75=\frac{347}{\lambda} and

\lambda=\frac{347}{75} so

\lambda=4.6m

7 0
2 years ago
An electromagnetic radio wave is received by a transmitter before it is converted to a sound wave. The radio wave has a waveleng
Dennis_Churaev [7]

Answer:

h5

Explanation:

h65hhrhry

3 0
2 years ago
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