A car is traveling at 21m/s. It accelerates at 1.4m/s2 for 11s. How fast is the car moving after the acceleration?
1 answer:
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Answer:
Explanation:
The two charges are q and Q - q. Let the distance between them is r
Use the formula for coulomb's law for the force between the two charges
So, the force between the charges q and Q - q is given by
For maxima and minima, differentiate the force with respect to q.
For maxima and minima, the value of dF/dq = 0
So, we get
q = Q /2
Now
the double derivate is negative, so the force is maxima when q = Q / 2 .