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Anettt [7]
3 years ago
5

A car is traveling at 21m/s. It accelerates at 1.4m/s2 for 11s. How fast is the car moving after the acceleration?

Physics
1 answer:
nata0808 [166]3 years ago
3 0

Answer:

v=u+at

v=21+1.4(11)

v=21+15.4

v=36.4

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The floor of a railroad flatcar is loaded with loose crates having a coefficient of static friction of 0.320 with the floor. If
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Answer:  29.50 m

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f=m.a=μ*N= m*a= μ*m*g= m*a

then

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5 0
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active and passive secruity measures are employed to identify, detect, classify and analyze possible threats inside of which zon
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5 0
3 years ago
Read 2 more answers
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