Answer:
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Answer:
Potential at B would be 100V
Explanation:
The electric potential is defined as the work done to bring a unit positive charge from infinity to some point in the field.
We always determine the potential with respect to some reference point. Let the potential at A be zero. If the potential at B is V, then work done to bring charge q from A to B = qV
which is the electric potential energy.
If instead we use some charge Q, the electric potential <em>energy</em> will be QV, but the electric potential will always be V.
Answer:
A. 54.88m/s.
B. 153.66m
Explanation:
Data obtained from the question include:
Time (t) = 5.6 secs
A. Determination of the skydiver's downward velocity.
Time (t) = 5.6 secs
Acceleration due to gravity (g) = 9.8m/s²
Velocity (v) =..?
v = gt
v = 9.8 x 5.6
v = 54.88m/s
Therefore, the skydiver's downward velocity is 54.88m/s
B. Determination of the height below the helicopter.
Time (t) = 5.6 secs
Acceleration due to gravity (g) = 9.8m/s²
Height (H) =..?
H = ½gt²
H = ½ x 9.8 x 5.6²
H = 153.66m
Therefore, the height below the helicopter when the parachute opens is 153.66m.
Answer:
Distance = 22m
Displacement = 12 + 2 - 8 =6m