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Alenkinab [10]
3 years ago
13

What voltage must be applied to an 6 nF capacitor to store 0.14 mC of charge? Give answer in terms of kV.

Physics
1 answer:
levacccp [35]3 years ago
8 0

Answer:

V=23.3kV

Explanation:

Definition of the capacitance C, where a voltage V is applied and a charge Q is stored:

Q=C*V

We solve to find V:

V=Q/C=0.14*10^{-3}C/6*10^{-9}F)=2.33*10^{4}V=23.3kV

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Answer:

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Explanation:

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1 year ago
Provide an example of when momentum is conserved and explain your answer you can get 10 PTS if answered with a good explaination
dezoksy [38]

Answer:

m_1=8\ kg,\ m_2=6\ kg,\ v_1=12\ m/s, v_2=4\ m/s,\ v_1'=-6\ m/s,\ v_2'=28\ m/s

Explanation:

<u>Conservation of Momentum </u>

The total momentum of a system of two particles is

p=m_1v_1+m_2v_2

Where m1,m2,v1, and v2 are the respective masses and velocities of the particles at a given time. Then, the two particles collide and change their velocities to v1' and v2'. The final momentum is now

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The momentum is conserved if no external forces are acting on the system, thus

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Let's put some numbers in the problem and say

m_1=8\ kg,\ m_2=6\ kg,\ v_1=12\ m/s, v_2=4\ m/s,\ v_1'=-6\ m/s,\ v_2'=28\ m/s

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96+24=-48+168

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It means that when the particles collide, the first mass returns at 6 m/s and the second continues in the same direction at 28 m/s

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3 years ago
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