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Alenkinab [10]
3 years ago
13

What voltage must be applied to an 6 nF capacitor to store 0.14 mC of charge? Give answer in terms of kV.

Physics
1 answer:
levacccp [35]3 years ago
8 0

Answer:

V=23.3kV

Explanation:

Definition of the capacitance C, where a voltage V is applied and a charge Q is stored:

Q=C*V

We solve to find V:

V=Q/C=0.14*10^{-3}C/6*10^{-9}F)=2.33*10^{4}V=23.3kV

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Below is an attachment containing the solution.

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