Julianne’s displacement from her origin is equal to 10.015 kilometers.
<u>Given the following data:</u>
- Distance B = 8.5 km, Northeast.
To calculate Julianne’s displacement from her origin:
<h3>How to calculate displacement.</h3>
We would denote the two (2) unit vectors along the East and Northeast directions by i and j respectively.
<u>Note:</u> Northeast is at angle of 45° with the East.
In terms of vectors, the distances becomes:
Distance A = 2i
![Distance\;B=8.5 [(cos 45i + sin 45j)]\\\\Distance\;B=(\frac{8.5}{\sqrt{2} } i \;+\;\frac{8.5}{\sqrt{2} } j)](https://tex.z-dn.net/?f=Distance%5C%3BB%3D8.5%20%5B%28cos%2045i%20%2B%20sin%2045j%29%5D%5C%5C%5C%5CDistance%5C%3BB%3D%28%5Cfrac%7B8.5%7D%7B%5Csqrt%7B2%7D%20%7D%20i%20%5C%3B%2B%5C%3B%5Cfrac%7B8.5%7D%7B%5Csqrt%7B2%7D%20%7D%20j%29)
<u>For the </u><u>resultant displacement</u><u>:</u>
D = 10.015 kilometers.
Read more on displacement here: brainly.com/question/13416288
Answer:
Springs are made of a variety of materials including copper and various forms of steel. The most common is high carbon steel as it is cheap, easy to work and a couple of other important properties.
Copper springs exist as well, but copper is more expensive than steel. However, in an environment where corrosion resistance is important, copper springs are a good alternative.
Explanation:
Answer:
10042.6 ohm
Explanation:
f = 10 kHz = 10000 Hz, L = 36 mH = 0.036 H, R = 10 kilo Ohm = 10000 ohm
C = 5 nF = 5 x 10^-9 F
XL = 2 x π x f x L
XL = 2 x 3.14 x 10000 x 0.036 = 2260.8 ohm
Xc = 1 / ( 2 x π x f x C) = 1 / ( 2 x 3.14 x 10000 x 5 x 10^-9)
Xc = 3184.7 ohm
Total impedance is Z.
Z^2 = R^2 + (XL - Xc)^2
Z^2 = 10000^2 + ( 2260.8 - 3184.7 )^2
Z = 10042.6 ohm
Answer: The magnitude of the current in the second wire 2.67A
Explanation:
Here is the complete question:
Two straight parallel wires are separated by 7.0 cm. There is a 2.0-A current flowing in the first wire. If the magnetic field strength is found to be zero between the two wires at a distance of 3.0 cm from the first wire, what is the magnitude of the current in the second wire?
Explanation: Please see the attachments below
