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3 years ago

What kind of reaction does luminol go through?

1 answer:

7 0

Answer: This reaction is called as Chemiluminescence. A type of reaction in which light is produced due to chemical reaction. While in case of Phosphorescence and Fluorescence light is emitted due to absorption of photons.

Explanation: i looked the answer up but your welcomee ❤

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Veronica is taking an average of 16 height measurements in a brand-new experiment. Which term is this the best example of? repli

Karolina [17]

Answer:

repetition

Explanation:

Taking an average of 16 height measurements is an example of repetition. Repetition involves making and taking repeated measurements in an experiment.

The goal is to achieve a highly accurate and precise data from the experiment.

Replication involves duplicating another experiment and testing to see how valid they are.
Since Veronica's experiment is a brand new one, it's hypothesis has not been tested or replicated in any way.
Therefore, it is not a replication.
But she is repeating the experiment to obtain different values.

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4 years ago

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Many scientists have contributed to the current accepted atomic model. Which of the following would be a reasonable description

jek_recluse [69]

Wheres the model at?

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4 years ago

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1. Aluminium reacts with chlorine to produce aluminium chloride. The balanced reaction is:

Anton [14]

Answer:

Explanation:

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3 years ago

A gas expands from a volume of 2.00L at 36.0oC to a volume of 2.50 L, what is the final temperature, if the pressure is constant

lakkis [162]

We shall consider V, the volume and T, the temperature.
According to Boyle's Laws:
$\frac{V1}{T1} = \frac{V2}{T2}$
In our case:
$\frac{2.00}{36.0} = \frac{2.50}{T2} =\ \textgreater \ T2= \frac{2.50*36.00}{2.00} = 45$

6 0

4 years ago

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The decomposition of hydrogen peroxide was studied, and the following data were obtained at a particular temperature: Time (s) (

harina [27]

Answer:

Part a: The rate of the equation for 1st order reaction is given as $Rate=k[H_2O_2]$

Part b: The integrated Rate Law is given as $[H_2O_2]=[H_2O_2]_0 e^{-kt}$

Part c: The value of rate constant is $7.8592 \times 10^{-4} s^{-1}$

Part d: Concentration after 4000 s is 0.043 M.

Explanation:

By plotting the relation between the natural log of concentration of $H_2O_2$ , the graph forms a straight line as indicated in the figure attached. This indicates that the reaction is of 1st order.

Part a

Rate Law

The rate of the equation for 1st order reaction is given as

$Rate=k[H_2O_2]$

Part b

Integrated Rate Law

The integrated Rate Law is given as

$[H_2O_2]=[H_2O_2]_0 e^{-kt}$

Part c

Value of the Rate Constant

Value of the rate constant is given by using the relation between 1st two observations i.e.

t1=0, M1=1.00

t2=120 s , M2=0.91

So k is calculated as

$-k(t_2-t_1)=ln{\frac{M_2}{M_1}}\\-k(120-0)=ln{\frac{0.91}{1.00}}\\k=\frac{-0.09431}{-120}\\k=7.8592 \times 10^{-4} s^{-1}$

The value of rate constant is $7.8592 \times 10^{-4} s^{-1}$

Part d

Concentration after 4000 s is given as

$-k(t_2-t_1)=ln{\frac{M_2}{1.0}}\\-7.8592 \times 10^{-4}(4000-0)=ln{\frac{M_2}{1.00}}\\-3.1437=ln{\frac{M_2}{1.00}}\\M_2=e^{-3.1437}\\M_2=0.043 M$

Concentration after 4000 s is 0.043 M.

7 0

3 years ago