Answer:
A
Explanation:
Ball bounces because of the difference in the air pressure on the outside of the ball, and opposite the point of impact, and the pressure inside of the ball. This means that the inside of the ball now has less space to contain the air molecules contained inside the ball, increasing the pressure inside the ball.
The average atomic mass of Sn is 118.71 g/mol
the percentage of heaviest Sn is 5.80%
the given mass of Sn is 82g
The total moles of Sn will be = mass / atomic mass = 82/118.71=0.691
Total atoms of Sn in 82g = ![6.023X10^{23}X0.691=4.16X10^{23}](https://tex.z-dn.net/?f=6.023X10%5E%7B23%7DX0.691%3D4.16X10%5E%7B23%7D)
the percentage of heaviest Sn is 5.80%
So the total atoms of
= 5.80% X ![4.16X10^{23}](https://tex.z-dn.net/?f=4.16X10%5E%7B23%7D)
Total atoms of
=
atoms
the mass of
will be = ![\frac{2.41X10^{22}X124}{6.023X10^{23}}=4.96g](https://tex.z-dn.net/?f=%5Cfrac%7B2.41X10%5E%7B22%7DX124%7D%7B6.023X10%5E%7B23%7D%7D%3D4.96g)
Answer:
![a=4.213cm](https://tex.z-dn.net/?f=a%3D4.213cm)
![r=1.490x10^{-8}cm](https://tex.z-dn.net/?f=r%3D1.490x10%5E%7B-8%7Dcm)
Explanation:
Hola.
En este caso, para calcular la longitud (a) de una cara de celda unitaria, consideramos la siguiente ecuación:
![\rho =\frac{#at*M}{a^3N_A}](https://tex.z-dn.net/?f=%5Crho%20%3D%5Cfrac%7B%23at%2AM%7D%7Ba%5E3N_A%7D)
En la que consideramos el número de átomos por celda (4 para FCC), la masa molar (40.3 g/mol para MgO) y el número de avogadro para obtener:
![3.581g/mol = \frac{4atom/celda*40.3g/mol}{a^3*6.02x10^{23}atom/mol}](https://tex.z-dn.net/?f=3.581g%2Fmol%20%3D%20%5Cfrac%7B4atom%2Fcelda%2A40.3g%2Fmol%7D%7Ba%5E3%2A6.02x10%5E%7B23%7Datom%2Fmol%7D)
Despejando para a, obtenemos:
![a^3 = \frac{4atom/celda*40.3g/mol}{3.581g/cm^3*6.02x10^{23}atom/mol}\\\\a=\sqrt[3]{7.478cm^3} \\\\a=4.213cm](https://tex.z-dn.net/?f=a%5E3%20%3D%20%5Cfrac%7B4atom%2Fcelda%2A40.3g%2Fmol%7D%7B3.581g%2Fcm%5E3%2A6.02x10%5E%7B23%7Datom%2Fmol%7D%5C%5C%5C%5Ca%3D%5Csqrt%5B3%5D%7B7.478cm%5E3%7D%20%5C%5C%5C%5Ca%3D4.213cm)
Finalmente, el radio lo calculamos como:
![r=\frac{\sqrt{2}*a}{4}=\frac{\sqrt{2}*4.213x10^{-8}cm}{4}\\\\r=1.490x10^{-8}cm](https://tex.z-dn.net/?f=r%3D%5Cfrac%7B%5Csqrt%7B2%7D%2Aa%7D%7B4%7D%3D%5Cfrac%7B%5Csqrt%7B2%7D%2A4.213x10%5E%7B-8%7Dcm%7D%7B4%7D%5C%5C%5C%5Cr%3D1.490x10%5E%7B-8%7Dcm)
¡Saludos!