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charle [14.2K]
2 years ago
9

What aspect of metallic bonding is responsible for malleability ductility and conductivity of metals?

Chemistry
1 answer:
ANTONII [103]2 years ago
4 0
Bonds are forces of attractions between atoms formed by the transfer of electrons or sharing of electrons. Metallic bond is a type bond that exist in metallic structures where the atoms of the metals attracts the sea of electrons in the structure.It is these metallic bonds that results to the malleability , ductility and conductivity of metals because in that the sea of electrons makes them conduct electricity. In addition the atoms of metals in the structure are ions which can slide past each other in the sea of electrons.
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True or false certain cations are associated with either exotermic or endothermic processes
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Explanation:

i think it is exothermic processes

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I AM GIVING AWAY 80 POINTS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
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In the gaseous state, chlorine exists as a diatomic molecule Cl2 (Molar mass = 70.9 g/mol). Calculate the number of moles of chl
kap26 [50]

Cl is stable as a diatomic molecule where the 2 Cl atoms are held together by a covalent bond

molar mass of the diatomic molecule is 70.9 g/mol

therefore 70.9 g of Cl₂ is - 1 mol

then 140 g of Cl₂ is - 1/70.9 x 140 = 1.97 mol

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8 0
3 years ago
How would you distinguish benzoic acid and benzyl alcohol by their infrared spectra?
Vadim26 [7]

The OH peaks in the IR spectra of benzyl alcohol and benzoic acid should be compared and contrasted.

<h3>What is the IR spectra of Benzoic acid?</h3>
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<h3>What is the IR spectra of Benzyl alcohol?</h3>
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<h3>What is IR spectra?</h3>

The percent transmittance (or absorbance) of the radiation through the molecule against the radiation's wave number forms the IR spectrum.

Learn more about IR spectra here:

brainly.com/question/22033021

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3 0
1 year ago
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The temperature inside your freezer is 0 degrees Celsius. You place a balloon with an initial temperature of 30 degrees C and a
blsea [12.9K]

Answer:

V=0.68L

Explanation:

For this question we can use

V1/T1 = V2/T2

where

V1 (initial volume )= 0.75 L

T1 (initial temperature in Kelvin)= 303.15

V2( final volume)= ?

T2 (final temperature in Kelvin)= 273.15

Now we must rearrange the equation to make V2 the subject

V2= (V1/T1) ×T2

V2=(0.75/303.15) ×273.15

V2=0.67577931717

V2= 0.68L

4 0
3 years ago
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