What would happen to Earth if it stopped in its orbit around the sun?

In one or two sentences, explain the difference between displacement and distance traveled.

34kurt

Answer: Distance doesn't specify direction but displacement do.

Explanation:

Distance specifies how far an object has gone, it doesn't specify direction of the object compared to displacement that is distance covered by a body in a specified direction.

Distance is therefore a scalar quantity i.e quantity that specifies only magnitude but no direction but displacement is vector quantity that specifies both magnitude and direction.

8 0

3 years ago

Most landfills contain very little air and moisture, which many microorganisms need to survive. How do you think these condition

Orlov [11]

Since substances break down much faster under aerobic conditions, as oxygen helps break the molecules apart, in a process called oxidation, biodegradation that actually takes place does so slowly that effects may not be visible in decades after a product was buried, if even then.

7 0

4 years ago

A horizontal disk rotates about a vertical axis through its center. Point P is midway between the center and the rim of the disk

rjkz [21]

If the disk turns with constant angular velocity, the following statements about it are true

The linear acceleration of Q is twice as great as the linear acceleration of P
is moving twice Q as fast as P.

Answer: Options D and E

Explanation:

Let us consider that R is the radius of the circular disc. So as Q is on the rim, so the distance of Q from the centre of the disc is R and as P is the midpoint between centre and rim of the disk, so the distance of P from the centre is R/2.

As we know that the angular velocity of the circular disk will be equal to the ratio of distance covered by that point to the time taken. So the angular velocity at point Q will be

$\text { Angular velocity at point } Q=\frac{\text { Distance covered by point } Q}{\text { Time }}=\frac{2 \pi R}{T}=v$

As R is the distance of point Q from the centre of the disc.

Similarly ,

$\text { Angular velocity at point } P=\frac{\text { Distance covered by point } P}{\text { Time }}=\frac{2 \pi\left(\frac{\mathrm{R}}{2}\right)}{T}=\frac{\pi R}{T}=v^{\prime}$

So if we equate v with v’ we obtain that

$v=2 v^{\prime}$

Therefore, the point Q will be moving twice as fast as P. As the velocity of Q is more than O, the linear acceleration of point Q will also be twice as great as the linear acceleration of P.

This is because acceleration is directly proportional to the rate of change in velocity. So if velocity increases in the factor of 2, the acceleration of point Q will also increase twice with respect to point P.

5 0

4 years ago

A fuzzy bunny sees a butterfly and chases it right off of a 20 m high cliff at 7m/s

bogdanovich [222]

A) 2.02 s

To find the time it takes for the bunny to reach the rocks below the cliff, we just need to analyze its vertical motion. This motion is a free fall motion, which is a uniformly accelerated motion. So we can use the suvat equation:

$s=u_y t+\frac{1}{2}at^2$

where

s is the vertical displacement

u is the initial vertical velocity

a is the acceleration

t is the time

For the bunny here, choosing downward as positive direction,

$u_y = 0$ (initial vertical velocity is zero)

s = 20 m

$a=g=9.8 m/s^2$ (acceleration of gravity)

And solving for t, we find the time of flight:

$t=\sqrt{\frac{2s}{g}}=\sqrt{\frac{2(20)}{9.8}}=2.02 s$

B) 14.1 m

For this part, we need to consider the horizontal motion of the bunny.

The horizontal motion of the bunny is a uniform motion with constant velocity, which is the initial velocity of the bunny:

$v_x = 7 m/s$

Therefore the distance covered after time t is given by

$d=v_x t$

And substituting the time at which the bunny hits the ground,

t = 2.02 s

We find how far the bunny went from the cliff:

$d=(7)(2.02)=14.1 m$

C) 21.0 m/s at $70.5^{\circ}$ below the horizontal

The horizontal component of the velocity is constant during the entire motion, so it will still be the same when the bunny hits the ground:

$v_x = 7 m/s$

Instead, the vertical velocity is given by

$v_y = u_y +at$

And substituting t = 2.02 s, we find the vertical velocity at the moment of impact:

$v_y = 0+(9.8)(2.02)=19.8 m/s$

So, the magnitude of the final velocity is

$v=\sqrt{v_x^2+v_y^2}=\sqrt{7^2+(19.8)^2}=21.0 m/s$

And the angle is given by

$\theta=tan^{-1}(\frac{v_y}{v_x})=tan^{-1}(\frac{19.8}{7})=70.5^{\circ}$

below the horizontal

5 0

3 years ago

How many grams of Li3N can be formed from 1.75 moles of Li? Assume an excess of nitrogen. 6 Li(s) + N2(

IceJOKER [234]

The balance chemical reaction is:

6 Li(s) + N2(g) → 2 Li3N(s)

We use the amount of the Lithium reactant and the relations of the substances from the reaction to calculate the amount of product produced. We do as follows:

1.75 mol Li ( 2 mol Li3N / 6 mol Li ) (34.83 g / mol) = 20.32 g Li

8 0

3 years ago