What is the value of X?<br> A. 5<br> B. 2.5<br> C.7.5<br> D. 10

Please help me!!!!!!!!!!!!!!!

Ainat [17]

r = 7.53 so d = 2r = 2(7.53) = 15.06 cm

Area of square = d^2 / 2 = (15.06)^2 / 2 = 113.41 cm^2

Area of circle = 3.14 (7.53)^2 = 178.04 cm^2

Area of yellow region = Area of circle - Area of square

Area of yellow region = 178.04 cm^2 - 113.41 cm^2

Area of yellow region =64.63 cm^2 = 64.6 cm^2 (nearest tenth)

Answer

64.6 cm^2

7 0

3 years ago

The circle below has center C, and its radius is 5 in. Given that m

yan [13]

What is the question bruh not everybody know what you talkin bout

7 0

3 years ago

(−t 4 −5t 3 −10t 2 )+(9t 3 +3t 2 −1)

klemol [59]

Answer:

$\left(-t^4-5t^3-10t^2\right)+\left(9t^3+3t^2-1\right)=-t^4+4t^3-7t^2-1$

Step-by-step explanation:

Given the expression

$\left(-t^4\:-5t^3\:-10t^2\:\right)+\left(9t^3\:+3t^2\:-1\right)$

Remove parentheses: (a)=a

$=-t^4-5t^3-10t^2+9t^3+3t^2-1$

Group like terms

$=-t^4-5t^3+9t^3-10t^2+3t^2-1$

Add similar elements

$=-t^4-5t^3+9t^3-7t^2-1$ ∵ $-10t^2+3t^2=-7t^2$

Add similar elements

$=-t^4+4t^3-7t^2-1$ ∵ $-5t^3+9t^3=4t^3$

Thus, the equivalent expression in simplified form:

$\left(-t^4-5t^3-10t^2\right)+\left(9t^3+3t^2-1\right)=-t^4+4t^3-7t^2-1$

4 0

3 years ago

Find the values of X and Y that makes these triangles congruent by the HL theorem

muminat

Answer:

C. x = 3, y = 2

Step-by-step explanation:

If both triangles are congruent by the HL Theorem, then their hypotenuse and a corresponding leg would be equal to each other.

Thus:

x + 3 = 3y (eqn. 1) => equal hypotenuse

Also,

x = y + 1 (eqn. 2) => equal legs

✔️Substitute x = y + 1 into eqn. 1 to find y.

x + 3 = 3y (eqn. 1)

(y + 1) + 3 = 3y

y + 1 + 3 = 3y

y + 4 = 3y

y + 4 - y = 3y - y

4 = 2y

Divide both sides by 2

4/2 = 2y/2

2 = y

y = 2

✔️ Substitute y = 2 into eqn. 2 to find x.

x = y + 1 (eqn. 2)

x = 2 + 1

x = 3

8 0

3 years ago

In the U.S., 95% of children have received their DTaP vaccine. Calculate the probability that fewer than 700 out of a sample of

Studentka2010 [4]

Answer:

0.0183

Step-by-step explanation:

The percentage of students, who received their DTaP vaccine is 95%.

This implies that:

$p = 0.95$

and

$q = 1 - 0.95 = 0.05$

The standard deviation of the proportion is

$= \sqrt{ \frac{pq}{n} }$

$= \sqrt{ \frac{0.95 \times 0.05}{750} } \\ = 0.00796$

We want to find the probability, that the sample proportion,

$\hat p \leqslant \frac{700}{750} \\ \hat p \leqslant 0.9 \bar3$

$P(\hat p\le0.9\bar3)=P(Z\le \frac{0.9 \bar3 - 0.95 }{0.00796} ) \\ = P(Z\le - 2.09) \\ = 0.0183$

5 0

3 years ago

What is the value of X? A. 5 B. 2.5 C.7.5 D. 10