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Naya [18.7K]
3 years ago
12

Please help me if you can, thank you!

Mathematics
1 answer:
strojnjashka [21]3 years ago
7 0
The discount was
  15%×$275 = $41.25
so the price at which the system was sold was
  $275.00 - 41.25 = $233.75

The sales person receives 2% of this, or
  2%×$233.75 ≈ $4.68
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5x−4≥12 AND 12x+5≤−4
bekas [8.4K]

Answer:

No solutions

Step-by-step explanation:

5x - 4 ≥ 12

<em>Isolate the Variable</em>

5x ≥ 16

<em>Divide both sides by 5</em>

x ≥ 3.2

AND

12x + 5 ≤ -4

<em>Isolate the Variable</em>

12x ≤ -9

<em>Divide both sides by 12</em>

x ≤ -.75

When you say and, you find the area that is covered by both inequalities, but because the inequalities solution sets don't overlap, there are no solutions.

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4 years ago
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Find the volume of a sphere with a diameter of 6.2 in.
Vsevolod [243]

Answer: its 23 meters

Step-by-step explanation:

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3 years ago
140 + (-122) + (-10), I also need it with work.
Aleks04 [339]

Answer:

8

Step-by-step explanation:

140-122=18

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3 years ago
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Please help me to solve this . Thank you so much .
worty [1.4K]

Answer:

a) N

b) L

c) area I

d) area II

e) area VI

Step-by-step explanation:

a) the points that are 2cm from R are Q, N, M, S. Then, points that are 4cm from P are K, N, R. So, the only one point that works for both is N.

b) the points that are >2cm from R are P, K, L, T. We do not count those are exactly 2cm from R. Then, points that are 4cm from T are R, M, L. Ans is L.

c) <4cm from P, are area I and II. Then area that are >2cm from R are I, VI, and V. So, the only area that works for both is I.

d) <2cm from R, are areas II, III, and IV. Then, <4cm from P, are areas I and II. So, the only one works for both is area II.

e) >4cm from T, are areas I, II, III, VI. Then, >4cm from P, are III, IV, V, VI. Finally, >2cm from R, are areas I, VI, V. The only one that works for all three conditions is area VI.

5 0
4 years ago
Fifty-five percent of what number is 27.5?
adelina 88 [10]

Answer:

50

Step-by-step explanation:

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3 years ago
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