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3 years ago

12

Auto-Check Motors charged Mr. Jones $84.00 for an automotive part plus $68.00 per hour that a mechanic worked to install the par

t. The total charge was $353.00. For about how long did the mechanic work to install the part on Mr. Jones’s car?

1 answer:

nexus9112 [7]3 years ago

8 0

Answer: The mechanic worked 3hrs 95 minutes

Step-by-step explanation:

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Well , in 3 hours , the amount of the tank that will be filled with pipe A = 8,000 x 3 = 24,000 L

Pipe could empty that 24,000 L in 3 hours.

So the capacity is around 6 - 8 L . .. . we need additional information to find out for sure

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45% of what number is 27

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Step-by-step explanation:

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A 2000-gallon metal tank to store hazardous materials was bought 15 years ago at cost of $100,000. What will a 5,000-gallon tank

harkovskaia [24]

Answer:

The value is $P_o = \$ 561958.9$

Step-by-step explanation:

From the question we are told that

The capacity of the metal tank is $C = 2000 \ gallon$

The duration usage is $t = 15\ years \ ago$

The cost of 2000-gallon tank 15 years ago is $P = \$100,000$

The capacity of the second tank considered is $C_1 = 5,000$

The power sizing exponent is $e = 0.57$

The initial construction cost index is $u_1 = 180$

The new construction after 15 years cost index is $u_2 =600$

Equation for the power sizing exponent is mathematically represented as

$\frac{P_n}{P} = [\frac{C_1}{C} ]^{e}$

=> Here $P_n$ is the cost of 5,000-gallon tank as at 15 years ago

So

$P_n = [\frac{5000}{2000} ] ^{0.57} * 100000$

$P_n = \$168587.7$

Equation for the cost index exponent is mathematically represented as

$\frac{P_o}{P_n} = \frac{u_2}{u_1}$

Here $P_o$ is the cost of 5,000-gallon tank today

So

$\frac{P_o}{168587.7} = \frac{600}{180}$

=> $P_o = \frac{600}{180} * 168587.7$

=> $P_o = \$ 561958.9$

8 0

3 years ago