Answer:
nota entonces jwbsbsbwhe de un 2
Answer:
(1,2)
y=2
x=1
Step-by-step explanation:
x+y=3
3x+5y=13
solve the equation
x=3-y
3x+5y=13
substitute the value of x into an equation
3(3-y)+5y=13
distribute
9-3y+5y=13
add -3y to 5y
9+2y=13
subtract 9 from both sides
2y=4
divide both sides by 2
y=2
substitute the value of y into an equation
x=3-2
subtract 3 to 2
x=1
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(1,2)
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Answer:
|-5|>4
Step-by-step explanation:
Negative 5 in absolute value is 5 since any number in absolute value turns out positive or at the very least 0. 5 is greater than 4, so |-5|>4.
0 and 1 are neither prime nor composite. A prime is any number greater than 1 that has just 1 and itself as factors. Primes can only start at x > 1
When that happens (when you start with numbers greater than one) p^2 is a composite consisting of 2 primes, so any composite will obey the law that he number will have at least 3 factors making it up -- in this case p p^2 and 1.
So the answer to the question by definition is that 0 numbers can have the property of both p and p^2 to be prime.