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sashaice [31]
2 years ago
15

12x +10+3+8x ? What do I have to do ?

Mathematics
2 answers:
WITCHER [35]2 years ago
8 0

Answer:

You have to do like terms

Step-by-step explanation:

12x+10+8+8x

12x+8x = 20x

10+3 = 13

your answer would be

20x+10

Annette [7]2 years ago
4 0

Simplifying

12x + 10 + 3 + 8x = 0

Reorder the terms:

10 + 3 + 12x + 8x = 0

Combine like terms: 10 + 3 = 13

13 + 12x + 8x = 0

Combine like terms: 12x + 8x = 20x

13 + 20x = 0

Solving

13 + 20x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-13' to each side of the equation.

13 + -13 + 20x = 0 + -13

Combine like terms: 13 + -13 = 0

0 + 20x = 0 + -13

20x = 0 + -13

Combine like terms: 0 + -13 = -13

20x = -13

Divide each side by '20'.

x = -0.65

Simplifying

x = -0.65

You might be interested in
(4.1.4) Let X and Y be Bernoulli random variables. Let Z = X + Y. a. Show that if X and Y cannot both be equal to 1, then Z is a
Fynjy0 [20]

Step-by-step explanation:

Given that,

a)

X ~ Bernoulli (p_x) and Y ~ Bernoulli (y_x)

X + Y = Z

The possible value for Z are Z = 0 when X = 0 and Y = 0

and Z = 1 when X = 0 and Y = 1 or when X = 1 and Y = 0

If X and Y can not be both equal to 1 , then the probability mass function of the random variable Z takes on the value of 0 for any value of Z other than 0 and 1,

Therefore Z is a Bernoulli random variable

b)

If X and Y can not be both equal to  1

then,

p_z = P(X=1 or Y=1)\\

p_z = P(X=1)+P(Y=1)-P(=1 and Y =1)

p_z = P(x=1)+P(Y=1)\\\\p_z=p_x+p_y

c)

If both X = 1 and Y = 1 then Z = 2

The possible values of the random variable Z are 0, 1 and 2.

since a  Bernoulli variable should be take on only values 0 and 1 the random variable Z does not have Bernoulli distribution

7 0
2 years ago
I need help on B and C. Not sure how I can solve those. Can someone please help me out here? Thank you for your help!
Valentin [98]

Nice job with part A on getting those correct answers.

====================================================

Part B

  • mu = mean = 43
  • sigma = standard deviation = 3

Let's calculate the z score for the raw score x = 37

z = (x - mu)/sigma

z = (37 - 43)/3

z = -6/3

z = -2

A negative z score tells us we're below the mean. Specifically, we are exactly 2 standard deviations under the mean.

If you repeat those steps for x = 46 (not changing mu or sigma), then you should get z = 1. So we're now 1 standard deviation above the mean.

Ultimately, we want to know the area under the standard normal curve (aka z curve) from z = -2 to z = 1.

Refer to the chart below which is a breakdown of the Empirical Rule. The pink areas are within 1 standard deviation of the mean. We have two regions taking up roughly 34% of the full area under the curve, so they combine to 34+34 = 68%

Then we add on another 13.5% which is the blue area on the left (between z = -2 and z = -1)

So 13.5+68 = 81.5% of the area under the curve is between z = -2 and z = 1.

<h3>Answer: 81.5</h3>

Note: the percent sign is already taken care of for us, so there's no need to type it in. But the answer above of course means 81.5% and that answer is approximate.

====================================================

Part C

Let's find the z score for x = 34. The values of mu and sigma are the same as before.

z = (x - mu)/sigma

z = (34-43)/3

z = -9/3

z = -3

So computing P(X > 34) is the same as P(Z > -3)

Notice how adding up all of the values in the chart mentioned gets us:

2.35+13.5+34+34+13.5+2.35 = 99.7

which means 99.7% of the distribution is within 3 standard deviations of the mean. The remaining 100% - 99.7% = 0.3% is the combined area of both tails. So each tail is (0.3%)/2 = 0.15%

In short, 0.15% of the area under the curve is to the left of z = -3

Therefore, 100% - 0.15% = 99.85% of the widgets are going to have z values larger than -3, which in turn means they have values larger than 34.

<h3>Answer: 99.85</h3>

Again you don't have to worry about the percent sign. Like before, the answer is approximate.

5 0
2 years ago
Find the value of csc theta, if cos =-3/5; 90 degrees &lt; theta &lt; 180 degrees
Sloan [31]

Answer:\frac{5}{4}

Step-by-step explanation:

Given

\cos \theta =\frac{-3}{5}

and \theta  lies between

90^{\circ}

and for this \theta,\sin and \text{cosec} is Positive as they lie in 2 nd Quadrant

\sin ^2\theta +\cos ^2\theta =1

\sin ^2\theta =1-(\frac{-3}{5})^2

\sin ^2\theta =1-\frac{9}{25}

\sin ^2\theta =\frac{16}{25}

\sin \theta =\frac{4}{5}

\therefore \text{cosec}\ \theta =\frac{5}{4}

6 0
2 years ago
Please help if you want brianleist (no links please!) Ty!
nikitadnepr [17]

Answer:

The answer is 40 can I please get brainleist

5 0
2 years ago
The endpoints of are A(2, 2) and B(3, 8). is dilated by a scale factor of 3.5 with the origin as the center of dilation to give
goldfiish [28.3K]

Answer:

The given line segment whose end points are A(2,2) and B(3,8).

Distance AB is given by distance formula , which is

if we have to find distance between two points (a,b) and (p,q) is

=  \sqrt{(p-a)^2+(q-b)^2}

AB= \sqrt{(3-2)^2+(8-2)^2}=\sqrt{1+36}=\sqrt{37} = 6.08 (approx)

Line segment AB is dilated by a factor of 3.5 to get New line segment CD.

Coordinate of C = (3.5 ×2, 3.5×2)= (7,7)

Coordinate of D = (3.5×3, 3.5×8)=(10.5,28)

CD = AB × 3.5

CD = √37× 3.5

     = 6.08 × 3.5

= 21.28 unit(approx)

2. Slope of line joining two points (p,q) and (a,b) is given by

m=\frac{q-b}{p-a}

m= \frac{8-2}{3-2}=6

As the two lines are coincident , so their slopes are equal.

Slope of line AB=Slope of line CD = 6




6 0
3 years ago
Read 2 more answers
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