Question

Use the method in the Example to find the square roots of 1 + √3i

Answer 1

Answer:

$\sqrt{1 + \sqrt{3} i}=\pm (1.58+i 0.548)$

Step-by-step explanation:

Given

z = 1 + √3 i

Let $\sqrt{1+\sqrt(3) i}=p+iq$

Squaring both sides

$1+\sqrt(3) i=p^2-q^2+2ipq$

Comparing real and imaginary part

Re(LHS)=Re(RHS)

$1=p^2-q^2$...........................(1)

comparing Im(LHS)=Im(RHS)

√3=2pq

$q=\frac{\sqrt{3}}{2p}$

Substitute q in equation (1)

$1=p^2-(\frac{\sqrt{3}}{2p})^2$

$p^4-p^2-0.75=0$

Let $x=p^2$

$x^2-x-0.75=0$

$x=\dfrac{1\pm \sqrt{1^2+4\times 0.75}}{2}$

$x=\frac{1\pm 4}{2}$

we take only Positive value because $p^2=x$

x=2.5  

$p^2=2.5$

thus $p=\pm 1.58$

$q=\pm 0.548$

thus,

$\sqrt{1 + \sqrt{3} i}=\pm (1.58+i 0.548)$