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zepelin [54]
3 years ago
5

What ordered pairs are solutions for the equation y=-2x+5

Mathematics
1 answer:
Shalnov [3]3 years ago
4 0

Answer:

( 0 , 5 ) , ( 1 , 3 ) ( 2 , 1 )

Step-by-step explanation:

1. x=0

y=-2(0)+5

y=5

( 0 , 5 )

2. x=1

y=-2(1)+5

y=-2+5

y=3

 ( 1 , 3 )

3. x=2

y=-2(2)+5

y=-4+5

y=1

( 2 , 1 )

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For what value is a is (a,9) a solution of the equation y=2x+1
yanalaym [24]

Answer:

a = 4

Step-by-step explanation:

y = 2x + 1 ......(1)

Going through y - y1 = m(x - x1)

m is slope and it is 2

y1 = 9 and x1 = a

y - 9 = 2(x - a)

y - 9 = 2x - 2a

y = 2x - 2a + 9 ........(2)

Equating (1) and (2)

2x + 1 = 2x - 2a + 9

Collecting like terms

2x - 2x + 2a = 9 - 1

2a = 8

a = 8/2

a = 4

7 0
3 years ago
What is the determinant of H=
Triss [41]

Answer:

The answer is -7

Step-by-step explanation:

I took the test! Hope this helps <3

4 0
3 years ago
Y+9÷2=y-3÷4-(y/3)<br>pls help​
Ann [662]

Answer:

y = - \frac{63}{4} or - 15.75

Step-by-step explanation:

Order of operations.

y + \frac{9}{2} = y - \frac{3}{4} - \frac{y}{3} Subtract y from each side.

y - y + \frac{9}{2} = y - y - \frac{3}{4} - \frac{y}{3}

\frac{9}{2} =  - \frac{3}{4} - \frac{y}{3}   Add \frac{3}{4} to each side

\frac{9}{2} + \frac{3}{4} = - \frac{3}{4} + \frac{3}{4} - \frac{y}{3}

\frac{9}{2} + \frac{3}{4} = - \frac{y}{3}    Find the common denominator for \frac{9}{2} and \frac{3}{4}, which is 4

\frac{9}{2} * \frac{2}{2} + \frac{3}{4} = - \frac{y}{3}

\frac{18}{4} + \frac{3}{4} = - \frac{y}{3}

\frac{21}{4} = - \frac{y}{3}   Multiply each side by 3

\frac{21}{4}  * 3 = - \frac{y}{3} * 3

\frac{63}{4} = - y      Divide each side by -1

y = - \frac{63}{4} = - 15 \frac{3}{4}

y = - 15.75

3 0
3 years ago
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What is the value of h(3) multiplied by h(7)<br><br> P.S. I will give brainliest to the best answer
Eddi Din [679]

Answer:

21

Step-by-step explanation:

Because h(3) times h(7) is equal to 21.

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2.295 rounded out to be 2.30
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