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2 years ago

What is the distance between the following points?

Mathematics

1 answer:

vitfil [10]2 years ago

7 0

Answer:

Step-by-step explanation:

go up 7 then over 3, add them together and you got 10

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Use the distributive property to write an equivalent expression.<br> 9(9x+2y-6)

Marizza181 [45]

Step-by-step explanation:

Multiply the number outside the brackets to the numbers inside:

So,

9 * 9x = 81x

9 * 2y = 18y

9 x -6 = -54

So the simplified or equivalent expression is:

81x + 18y - 54

4 0

2 years ago

Subtract 9x2 + 73 – 2 from 8x – 10.

mrs_skeptik [129]

Answer:

8x-99

Step-by-step explanation:

18+73-2+16+73=89

8x-10 - 89 = 8x-99

6 0

3 years ago

Read 2 more answers

Can u help me answer this? A tree is 8.5 feet tall. It grows 0.75 feet each year.

alexandr1967 [171]

Hmm... 8.5 + 0.75y

0.75y + 8.5

5 0

3 years ago

What’s the slope of the line that passes through 5,10 and 7,12

Marrrta [24]

Slope of the line passes through (5,10) and (7,12) is 1.

Step-by-step explanation:

Given,

The two points are (5,10) and (7,12).

To find the slope passing through the given points.

Formula

The slope of the line passing through ( $x_{1} ,y_{1}$ ) and ( $x_{2} ,y_{2}$ ) is $\frac{y_{2} -y_{1} }{x_{2} -x_{1} }$

Now, putting $x_{1} =5,y_{1}=10, x_{2}=7, y_{2} =12$ we get,

Slope = $\frac{12-10}{7-5}$ = $\frac{2}{2}$ = 1

Hence,

Slope of the line passes through (5,10) and (7,12) is 1.

7 0

3 years ago

Read 2 more answers

The equation V = 16300 (0.94)^t represents the value (in dollars) of a car t years after its purchase. Use this equation to comp

Dafna1 [17]

Solution:

Given:

$V=16300(0.94)^t$

The value of a car after t - years will depreciate.

Hence, the equation given represents the value after depreciation over t-years.

To get the rate, we compare the equation with the depreciation formula.

$\begin{gathered} A=P(1-r)^t \\ \text{where;} \\ P\text{ is the original value} \\ r\text{ is the rate} \\ t\text{ is the time } \end{gathered}$

Hence,

$\begin{gathered} V=16300(0.94)^t \\ A=P(1-r)^t \\ \\ \text{Comparing both equations,} \\ P=16300 \\ 1-r=0.94 \\ 1-0.94=r \\ r=0.06 \\ To\text{ percentage,} \\ r=0.06\times100=6\text{ \%} \\ \\ \text{Hence, } \\ P\text{ is the purchase price} \\ r\text{ is the rate} \end{gathered}$

Therefore, the value of this car is decreasing at a rate of 6%. The purchase price of the car was $16,300.

5 0

1 year ago