Distinguish between homogeneous and heterogeneous mixture with 2 example each. Do not use the examples give above

1 answer:

dsp734 years ago

7 0

Homogeneous mixture is a mixture in which the composition is uniform throughout the mixture. While, heterogeneous mixture is a mixture in which the composition is not uniform throughout the mixture.
Example of heterogeneous :
Oil and water
Smog

Example of homogeneous:
Salt water
Air

You might be interested in

Why is carbon said to provide a “backbone” in many molecules?(1 point)

slega [8]

Answer:

The carbon atom has unique properties that allow it to form covalent bonds to as many as four different atoms, making this versatile element ideal to serve as the basic structural component, or “backbone,” of the macromolecules.

3 0

3 years ago

Urgent !!!

arsen [322]

The weight is not coming from the center of the mass because the force that act on it is not is equal is side.(2) section B donot have weight because the ruler bend down and section be raise up so no weight.

8 0

3 years ago

What will happen to an object's wavelength as the object moves towards you?

Ilia_Sergeevich [38]

The wavelength will get shorter

5 0

3 years ago

Read 2 more answers

A positively charged particle 1 is at the origin of a Cartesian coordinate system, and there are no other charged objects nearby

8090 [49]

Answer:

P=(2 nm, 8mn)

Explanation:

Given :

Position of positively charged particle at origin, $O=(0\ nm,0\ nm)$

Position of desired magnetic field, $D\equiv(1\ nm,8\ nm)$

Magnitude of desired magnetic field, $E=0\ N.C^{-1}$

Let q be the positive charge magnitude placed at origin.

<u>We know the distance between the two Cartesian points is given as:</u>

$d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

<u>For the electric field effect to be zero at point D we need equal and opposite field at the point.</u>

$\frac{1}{4\pi.\epsilon_0} \times \frac{q}{r^2 } =\frac{1}{4\pi.\epsilon_0} \times \frac{q}{r^2 }$

$\therefore (1-0)^2+(8-0)^2=r^2$

$r^2=65\ nm$

$r=\sqrt{65}$

as we know that the electric field lines emerge radially outward of a positive charge so the second charge will be at equally opposite side of the given point.

assuming that the second charge is placed at (x,y) nano-meters.

Therefore,

$x=2\times 1=2\ nm$