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OverLord2011 [107]
3 years ago
13

200. newton·meters of work is put into a machine over a distance of 20. meters. The machine does 150. newton·meters of work as i

t lifts a load 10. meters high. What is the mechanical advantage of the machine?
Physics
1 answer:
dezoksy [38]3 years ago
3 0

Answer:

Answer:

Mechanical advantage of the machine is 1.5

Explanation:

The formula for mechanical advantage is:

MA = OutputForce/InputForce

To calculate this, we need the force of input and the force of output.

The formula to calculate the force given the work (W) and the distance (d) is:

F = W/d

Calculating the input force Fi:

Fi = 200Nm/20m = 10 N

Calculating the output force Fo:

Fo = 150Nm/10m = 15 N

Thus, the mechanical advantage MA is:

MA = 15N / 10N = 1.5

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<h2>The child swing through the swing's equilibrium position 6 times during the course of 3 periods.</h2>

Explanation:

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Monochromatic light from a distant source is incident on a slit 0.750 mm wide. On a screen 2.00 m away, the distance from the ce
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Answer:

\lambda= 506.25 nm

Explanation:

Diffraction is observed when a wave is distorted by an obstacle whose dimensions are comparable to the wavelength. The simplest case corresponds to the Fraunhofer diffraction, in which the obstacle is a long, narrow slit, so we can ignore the effects of extremes.

This is a simple case, in which we can use the Fraunhofer single slit diffraction equation:

y=\frac{m \lambda D}{a}

Where:

y=Displacement\hspace{3}from\hspace{3} the\hspace{3} centerline \hspace{3}for \hspace{3}minimum\hspace{3} intensity =1.35mm\\\lambda=Light\hspace{3} wavelength \\D=Distance\hspace{3}between\hspace{3}the\hspace{3}screen\hspace{3}and\hspace{3}the\hspace{3}slit=2m\\a=width\hspace{3}of\hspace{3}the\hspace{3}slit=0.750mm\\m=Order\hspace{3}number=1

Solving for λ:

\lambda=\frac{y*a}{mD}

Replacing the data provided by the problem:

\lambda=\frac{(1.35\times 10^{-3})*(0.750\times 10^{-3})}{1*2} =5.0625\times 10^{-7}m =506.25nm

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